This function is a hyperbola. It graphs out two disjoint curves. A linear function produces a single straight line graph. All linear functions can be written in the form y = mx+b. The x being in the denominator is one indicator we cannot write the original equation in the form y = mx+b.

y = 3/x is the same as xy = 3; this tells us every point on y = 3/x has its (x,y) coordinate pair multiply to 3.

8 0

4 years ago

Which of the following are identities? Check all that apply. A. cot2x + 1 = csc2x B. tan2x = 1 - sec2x C. sin2x = 1 + cos2x D. s

kirill115 [55]

I'll assume those are squares. We know D is an identity:

$\sin^2 x + \cos ^2 x = 1$

Dividing through by $\sin ^2 x$

$1 + \cot^2 x = \csc^2 x$

That's A.

Dividing the original through by $\cos ^2 x$

$\tan^2 x + 1 = \sec^2 x$

Not quite B, wrong sign on tangent.

C has the wrong sign on cosine squared as well.

Identities: A & D

4 0

3 years ago