Hello,
The formula for finding the area of a circular region is:

then:

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

Now we can find its area:
![A_{2}=2* \frac{b*h}{2} \\ \\ A_{2}= [r*sen(40)][r*cos(40)]\\ \\A_{2}= r^{2}*sen(40)*cos(40)](https://tex.z-dn.net/?f=A_%7B2%7D%3D2%2A%20%5Cfrac%7Bb%2Ah%7D%7B2%7D%20%20%5C%5C%20%20%5C%5C%20A_%7B2%7D%3D%20%5Br%2Asen%2840%29%5D%5Br%2Acos%2840%29%5D%5C%5C%20%20%5C%5CA_%7B2%7D%3D%20r%5E%7B2%7D%2Asen%2840%29%2Acos%2840%29)
The subtraction of the two areas is 100cm^2, then:
Answer: r= 1.59cm
Seconded to the bottomed is symmetric property of equality
bottomed one is substitution property of equality
first one is reflexive property of equality <span />
Answer:
the sum of -4.82 and 4.35 = -0.47
so a is correct
the product of -4.82 and 4.35 = -20.967
so b is incorrect
the quotient of -4.82 and -4.35 is 1.10804597701
the quotient of 4.82 and 4.35 is 1.10804597701
so c is correct
if we subtract 4.35 from -4.82 we get -9.17
so d is incorrect
Hope This Helps!!!
Answer:
ok
Step-by-step explanation:
Answer:
See attached picture.
Step-by-step explanation:
To graph the line, start at (0,-3) since b = -3 in the equation. This is the y-intercept. Mark this point. From this point, move down 2 units and to the right 1 unit. Mark this new point at (1,-1). Connect the points with a line. See attached picture.