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3 years ago

7

A city has a population of 230,000 people. Suppose that each year the population grows by 8.5%. What will the population be afte

r 14
years?

1 answer:

worty [1.4K]3 years ago

6 0

Answer:

720,682.92

Step-by-step explanation:

8.5% = 0.085

P(t) = Initial Population * (1 + rate)t

P(t) = 230,000(1 + 0.085)t

P(t) = 230,000(1.085)t

P(14) = 230,000(1.085)14

P(14) = 720,682.82

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Think of a number, divide it by 5 and then add 27 to the result. The resulting number is half of the original number. What was t

Salsk061 [2.6K]

This Is One Answer, There Are More Then One Answer.

100 / 5 = 20 + 27 = 47 / 2 = 23.5

100 = my number
5 = divide by

100 / 5 = 20
27 = add
20 = results of last answer
Then 20 + 27 = 47
47 = results of last answer
2 = half of
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Answer:

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

Step-by-step explanation:

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Binomial probability distribution

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In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A study indicates that 62% of students have have a laptop.

This means that $n = 0.62$

You randomly sample 8 students.

This means that $n = 8$

Find the probability that between 4 and 6 (including endpoints) have a laptop.

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{8,4}.(0.62)^{4}.(0.38)^{4} = 0.2157$

$P(X = 5) = C_{8,5}.(0.62)^{5}.(0.38)^{3} = 0.2815$

$P(X = 6) = C_{8,6}.(0.62)^{6}.(0.38)^{2} = 0.2297$

$P(4 \leq X \leq 6) = P(X = 4) + P(X = 5) + P(X = 6) = 0.2157 + 0.2815 + 0.2297 = 0.7269$

72.69% probability that between 4 and 6 (including endpoints) have a laptop.

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Step-by-step explanation:

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