Triangle BCD has vertexes at B(2, 4), C(3, 3), and D(2, 3). Find the measure of angle C.

Lines c and d are intersected by line p. At the intersection of lines c and p, the bottom left angle is (3 x + 45) degrees. At t

anzhelika [568]

Answer:

its 18

Step-by-step explanation:

i just took the test on edg :)

4 0

4 years ago

The ratio of the areas of two rectangles is 2 to 3. If the area of the larger rectangle is 600 square feet, what is the area of

Andreyy89

Answer:

400sq.ft

Step-by-step explanation:

Let Area of smaller rectangle be x

➝2:3=x:600

➝2/3=x/600

➝2×600=3x

➝3x=1200

➝x=1200/3

➝x=400sq.ft

7 0

3 years ago

MATH HELP ASAP! MARKING BRAINLIST!!!!!! maTH haLLP

alexgriva [62]

It is a 75% increase

4 0

3 years ago

Read 2 more answers

On a coordinate plane, is translated 3 units up and 3 units to the right to create Line p is drawn through P and and Line q is d

Mandarinka [93]

Answer:

Lines p and q are parallel

Step-by-step explanation:

1) Completing the question:

On a coordinate plane, is translated 3 units up and 3 units to the right to create ′′. Line p is drawn through and ’, and Line is drawn through and ’. Which statement about Lines and is true?

2)

If PQ (x, y) according to that rule then P'Q' (x+3, y+3). So let's plot to answer the question. Setting numbers for,x and y.

3) As you can see below, since we add 3 units to the right and 3 units up then no x-coordinate must be the same, no y-coordinate must remain the same. In addition, p and q won't have the same intercept, neither x nor y.

5 0

4 years ago

An accounting firm is trying to decide between IT training conducted in-house and the use of the third party consultants. To get

Jlenok [28]

Answer:

$t=\frac{500-490}{\sqrt{\frac{48^2}{180}+\frac{32^2}{210}}}}=2.379$

$p_v =2*P(t_{388}>2.379)=0.0178$

Comparing the p value with the significance level provided $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and a would be a significant difference in the average of the two groups.

Step-by-step explanation:

Assuming the following info

IT Training N mean Stdev

In-house 210 $490 $32

Consultants 180 $500 $48

1) Data given and notation

$\bar X_{I}=490$ represent the mean for the sample of In-house

$\bar X_{C}=500$ represent the mean for the sample Consutants

$s_{I}=32$ represent the population standard deviation for the sample In-house

$s_{C}=48$ represent the population standard deviation for the sample Consultants

$n_{I}=210$ sample size for the group In-house

$n_{C}=180$ sample size for the group Consultants

t would represent the statistic (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

Null hypothesis: $\mu_{I}=\mu_{C}$

Alternative hypothesis: $\mu_{I} \neq \mu_{C}$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{C}-\bar X_{I}}{\sqrt{\frac{s^2_{C}}{n_{C}}+\frac{s^2_{I}}{n_{I}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

3) Calculate the statistic

With the info given we can replace in formula (1) like this:

$t=\frac{500-490}{\sqrt{\frac{48^2}{180}+\frac{32^2}{210}}}}=2.379$

4) Statistical decision

First we need to calculate the degrees of freedom given by:

$df=n_{C}+n_{I}-2=210+180-2=388[/tex[The sample is large enough to assume that the distribution is also normal.Since is a bilateral test the p value would be:
[tex]p_v =2*P(t_{388}>2.379)=0.0178$

Comparing the p value with the significance level provided $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and a would be a significant difference in the average of the two groups.

6 0

4 years ago