Answer:
6 and 11
Step-by-step explanation:
n1 = n + 5
ns^2 = 3 + 3nb
6^2 = 3 + 3(11)
36 = 3 + 33
11 = 6 + 5
Answer:
Amount = Initial value × (1 + rate of interest)^years and 374
Step-by-step explanation:
The formula to determine the student population and the estimated student population is given below:
As we know that
Amount = Initial value × (1 + rate of interest)^years
= 284 × (1 + 0.04)^7
= 284 × 1.04^7
= 373.72
= 374
Just comparing your (x, y) points to the values on the table, it looks like b) would be the quick answer. Since it states under the table to use average values within each range.
So for x=62 (the weight), we have y=122 (the iron count) which would be the average of the range between 115 and 129.
Similiarly, x=70 corresponds to y=146, which is the average of 139 and 153.
You could take the average values of your highest and lowest iron count ranges compare them to the max-min weight to get your slope. Looks like it would be (155-112)/(73-58)= 43/15= 2.8666 repeating. That would make sense with the slope in the equation listed in b) as well.
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<h3><u>
Answer:</u></h3>
- Your answer would be "30".
<h3><u>
Step-by-step explanation:</u></h3>
- 2x + 20 = 3x - 10 [Corresponding Angles]
- => 10 + 20 = 3x - 2x
- => 30 = x
<h3><u>Conclusion:</u></h3>
Therefore, your answer would be "30".
Hoped this helped.
Answer:
$38.31
Step-by-step explanation:
Given:
Pure silver that cost $33.48 per ounce used to form $24.35 alloy/ounce.
Question asked:
How many ounces of pure silver were used to make an alloy of silver costing $27.87 per ounce?
Solution:
At cost $24.35/ounce, pure silver is mixed = $33.48
At cost $1/ounce, pure silver is mixed = 
At cost $27.87/ounce, pure silver is mixed = 
Thus, $38.31 ounces of pure silver were used to make an alloy of silver costing $27.87 per ounce.
