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ohaa [14]
4 years ago
9

The function f(x) = 2(3.5)x is reflected across the x-axis to create g(x).

Mathematics
2 answers:
Wittaler [7]4 years ago
7 0

Answer:

Given the function f(x)= 2 (3.5)^x is reflected across the x-axis to create g(x).

The rule of reflection across x- axis is:  (x,y) \rightarrow (x , -y)

then;

f(x)=y = 2 (3.5)^x

using the rule of reflection across x-axis;

-y =2 (3.5)^x}  or  y= -2 (3.5)^x}

therefore, the function g(x) = -2 (3.5)^x}

Since, this g(x) is an exponential function it is of the form of ab^x where a is the initial value.

On comparing we get ;

The initial value of g(x) is -2.

Now, to find the output for inputs of -1 and 1 in g(x);

At x = -1

g(-1) =-2(3.5)^{-1} =-2 \cdot \frac{1}{3.5} = \frac{-20}{35} = - 0.572  and

at x = 1

g(1) =-2(3.5)^1 = -2 \cdot 3.5 = -7


Lapatulllka [165]4 years ago
3 0

g(x)=-2 (3.5)x

the initial value is -2

g(-1)=-0.57

g(1)=-7


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let x represent the leg length

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Read 2 more answers
Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$
horrorfan [7]

Answer:

A +B+C+D  = 3 is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

A+B+C+D = ? if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under \sqrt (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \   (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}

Comparing the above expression with:

$\frac{A\sqrt{B}+C}{D}$

A = 5, B = 6 (Not divisible by square of any prime)

C = -10

D = 2 (positive)

GCD of A, C and D is 1.

So, A +B+C+D = 5+6-10+2 = \bold3

5 0
4 years ago
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