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3 years ago

What is 4-(-37)+(8)-(34) Pls solve brainlliest

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

First we need to remove the parenthesis

4 + 37 + 8 - (34)

4 + 37 + 8 -34

Add 4 and 37

41 + 8 - 34

Add 41 and 8

49 - 34

Subtract

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The product of 2x-3 and x+4 can be expressed asA) 2x^2+5x-12B) 3x+1C) 2x^2+x-12D) 2x^2-12

DanielleElmas [232]

The given product is

$(2x-3)(x+4)$

We have to use the distributive property

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Then, we reduce like terms

$2x^2+5x-12$ <h2>Hence, the answer is A.</h2>

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1 year ago

212 -(72 divided by 2) = ___ -__=___

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3 years ago

Read 2 more answers

What’s 5.03 in simplest form

kondaur [170]

Answer:

5 3/10

Step-by-step explanation:

To simplify this decimal you need to convert it to a fraction

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3 years ago

If ST≅SV and m∠SUT=68°, what is m∠TUV?

artcher [175]

Answer:

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Step-by-step explanation:

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3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

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3 years ago