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Anon25 [30]
3 years ago
9

Identify the x-intercept and the y-intercept of the graph of 6x + 15y = −30.

Mathematics
1 answer:
Hunter-Best [27]3 years ago
5 0

Answer:

D. x-intercept is -5 and the y-intercept is -2

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-7(2x-3) equivalent expression
ollegr [7]

Answer:

-14x+21

Step-by-step explanation:

-7(2x-3)

-14x+21

5 0
3 years ago
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The three trapezoids have the same base lengths, but different angle measures. Which trapezoid has the greatest area? Explain.
Luden [163]

Steps I took:

I drew out a circle with a radius of 1 and drew a trapezoid inscribed in the top portion of it. I outlined the rectangle within the trapezoid and the two right triangles within it. This allowed me to come to the conclusion, using the pythagorean theorem, that the height of the trapezoid is <span><span>h=<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span></span><span>h=<span>1−<span><span>x2</span>4</span></span></span></span>

The formula for the area of a trapezoid is <span><span>A=<span><span>a+b</span>2</span>(h)</span><span>A=<span><span>a+b</span>2</span>(h)</span></span> I am basically solving for the <span>aa</span> here and so far I have:

<span><span>A=<span><span>x+2</span>2</span>(<span><span>1−<span><span>x2</span>4</span></span><span>−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span>1−<span><span>x2</span>4</span></span>)</span></span>

I simplified this in order to be able to easily take the derivative of it as such:

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span>4</span><span>−−−−−−</span>√</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>4</span>)</span></span>

<span><span>A=<span><span>x+2</span>2</span>(<span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>2</span>)</span><span>A=<span><span>x+2</span>2</span>(<span><span>4−<span>x2</span></span>2</span>)</span></span>

<span><span>A=(<span>14</span>)(x+2)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)</span><span>A=(<span>14</span>)(x+2)(<span>4−<span>x2</span></span>)</span></span>

Then I took the derivative:

<span><span><span>A′</span>=<span>14</span>[(1)(<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span><span><span>A′</span>=<span>14</span>[(1)(<span>4−<span>x2</span></span>)+(x+2)((<span>12</span>)(4−<span>x2</span><span>)<span>−1/2</span></span>(−2x)]</span></span>

This all simplified to:

<span><span><span>A′</span>=<span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]</span><span><span>A′</span>=<span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]</span></span>

Next, I set the derivative equal to zero in order to find the maximum point (I know that I can prove that it is actually a max point by taking the second derivative later)

<span><span><span>14</span>[<span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>]=0</span><span><span>14</span>[<span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>]=0</span></span><span><span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span>−<span><span>2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span>4−<span>x2</span></span>−<span><span>2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span><span>4−<span>x2</span></span><span>−−−−−</span>√</span></span>=0</span><span><span><span>4−<span>x2</span>−2<span>x2</span>−4x</span><span>4−<span>x2</span></span></span>=0</span></span><span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span><span>4−<span>x2</span>−2<span>x2</span>−4x=0</span></span><span><span>−3<span>x2</span>−4x+4=0</span><span>−3<span>x2</span>−4x+4=0</span></span>

so I got:

<span><span>x=−2orx=<span>23</span></span><span>x=−2orx=<span>23</span></span></span>

<span><span>x=−2</span><span>x=−2</span></span> wouldn't make sense so I chose <span><span>x=<span>23</span></span><span>x=<span>23</span></span></span> and plugged it back into my original formula for the area of this trapezoid but my answer doesn't seem to match any of the multiple choice solutions. Where did I go wrong?

calculus optimization
6 0
3 years ago
Read 2 more answers
In which quadrant does point K (7, −4) lie?
tester [92]
The point (7,-4) lies in Quadrant 4. Where it’s ( + , - )

hope this helps !
5 0
3 years ago
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Solve the equation for y.
gayaneshka [121]

Answer: C

Step-by-step explanation:

2x+5y=5

\mathrm{Subtract\:}2x\mathrm{\:from\:both\:sides}

2x+5y-2x=5-2x

\mathrm{Simplify}

5y=5-2x

\mathrm{Divide\:both\:sides\:by\:}5

\frac{5y}{5}=\frac{5}{5}-\frac{2x}{5}

\mathrm{Simplify}

\bf{y=-\frac{2}{5}x  + 1}

6 0
2 years ago
The sales tax rate for a local county is 8.9
morpeh [17]
Multiply the cost by the tax, but make sure you make the percentage into decimal form by dividing it by 100.

8.9/100 is 0.089.
0.089x361 is 32.129

Now add the tax due to the original cost.

32.129+361= 393.129

Now round your answer to the hundredths place (cannot have thousandths place when working with money)

$393.13
8 0
3 years ago
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