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3 years ago

Identify the x-intercept and the y-intercept of the graph of 6x + 15y = −30.

Mathematics

1 answer:

Hunter-Best [27]3 years ago

5 0

Answer:

D. x-intercept is -5 and the y-intercept is -2

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I need help. Only do number 34.

Svetach [21]

Answer:

Amplitude: 3

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Step-by-step explanation:

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2 years ago

What is 2/3x + 1/4x= 6 ??????

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2 years ago

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Cómo resolver un problema de matemáticas <br> 1 3<br> _ + _ =<br> 6. 4

Step2247 [10]

13 + -6.6=6.4 all I did was subtract 6.4 by 13 and I got 6.6 but then turned it negative to solve the equation

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3 years ago

Suppose you receive an allowance of $55 and your friend receives an allowance of $40 at the beginning of the month. If you spend

Licemer1 [7]

Answer: 5 days

Step-by-step explanation:

so we need to find:

55 - 6a = 40 - 3a

with a being the days we need to find

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+6a on each side

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divide each side by 3

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2 years ago

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

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3 years ago