SU would be the hypotenuse so you can use Pythagorean Theorem to solve this problem.
42^2 + 56^2 = c^2
1764 + 3136 = c^2
4900 = c^2
70 = c
6+7+8 6+8+7 7+6+8 8+7+6 7+8+6 and 8+6+7
5215 sq ft. S= p times h /2 +B
35*4 * 57/ 2. + 35*35
Got h=57 by a2+b2=c2
17.5 sq+ 55 sq =5215 sq rt of 5215 is 57
Answer:the answer is 18
Step-by-step explanation:You do 9minus three then get six and then multiply six by three to get 18.
We know: length of a rectangle is 7m less than three times the width.
So let's set the length to l, width to w.
And we can get that l = 3w-7.
We also know that the area of the rectangle is 66 m^2.
Thus, l*w= 66.
So we have:
function 1: l=3w-7
function 2: l*w=66
plug function 1 to 2.
(3w-7)*w=66
3w^2-7w-66=0
w=6 and -11/3.
And the width of a rectangle can not be negative.
So: w=6.
Plug w=6 back to function 1 or 2, either way is correct and can give you the length. In this case, I will plug it back to function 1.
l=3*6-7=11.
So: the width of the rectangle is 6, and the length of the rectangle is 11.
