Answer:
1.) 14.09 m/s
2.) 6.9 m/s
Step-by-step explanation:
Given that the boat is pointing North and can typically move at a speed of 12.8 m/s in calm waters. The boat travels through water where there is a 5.9 m/s current flowing to the East.
The speed of the boat relative to a stationary observer on land will be achieved by using pythagorean theorem
V^2 = 12.8^2 + 5.9^2
V^2 = 198.65
Square root both sides
V = 14.09 m/s
2.) If the boat turns to face directly West.
Since the boat can move at speed 12.8 m/s in a calm water, the speed of the boat if it face west will be
12.8 - 5.9 = 6.9 m/s
Therefore, the boat is moving relative to land at 6.9m/s
