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gladu [14]
3 years ago
12

Simplify 7h^2+6h^2+5h^2+6h^2-h^2

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

23h^2

Step-by-step explanation:

These are all like terms so we add/subtract them from left to right.

7h^2+6h^2+5h^2+6h^2-h^2

=   24h^2 - h^2

= 23h^2   (answer)

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How many roots do u thinn
hram777 [196]

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Step-by-step explanation:

Each equation is in vertex form, so you can easily determine the number of real roots. The leading coefficient tells you whether the parabola opens upward (positive) or downward (negative).

  y = a(x -h)^2 +k

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6 0
3 years ago
Find |−3/5|+3/4. Write your answer as a mixed number in simplest form.
cricket20 [7]

Answer:

1 7/20

Step-by-step explanation:

|-3/5|+3/4= 3/5+3/4

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4 0
3 years ago
Read 2 more answers
Machine at a manufacturing plant can make 16 of item A per hour or 20 of item B per hour. The machine runs for 24 hours a day. Y
irina [24]

Answer:

A + B = 24

16A + 20B = 434

Step-by-step explanation:

To write a system of equations for this scenario, let's say that A represents the number of hours machine A ran, and B represents the number of hours machine B ran.

The first equation will be:

A + B = 24

because the total number of hours ran is 24.

The second equation will be:

16A + 20B = 434

because the total number of items made is 434.

A + B = 24

16A + 20B = 434

First solve for one variable, and let's just do A.

Using the first equation, A + B = 24, A is equal to 24 - B.

Substitute this value to the second equation.

16 (24 - B) + 20B = 434

384 - 16B + 20B = 434

4B = 50

B = 12.5

Now use this value of B to find the value of A.

A + 12.5 = 24

A = 11.5

Machine A ran for 11.5 hours, and Machine B ran for 12 hours.

6 0
3 years ago
Suppose the position of an object moving in a straight line is given by s (t )equals 4 t2+ 5 t+ 5. Find the instantaneous veloci
VLD [36.1K]

Answer:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

Step-by-step explanation:

For this case we have the position function s(t) given by:

s(t) = 4t^2 + 5t+5

And we can calculate the instanteneous velocity with the first derivate respect to the time, like this:

v(t) = s'(t)= \frac{ds}{dt}

And if we take the derivate we got:

v(t) = 8t +5

And that represent the instantaneous velocity at a given time t.

And then we just need to replace t =2 in order to find the instantaneous velocity and we got:

v(t=2) = 8*2 + 5 = 16+5 = 21

4 0
3 years ago
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