Answer:
A) Each of the smaller donations is $20.
B) The larger donation is greater than the smaller donations by $15.
Step-by-step explanation:
4+4+7 is equal to 15, and divide 75 by 15 to get $5 per part. Multiply 4 by 5 to get $20 for a smaller donation, and 7 by 5 to get $35 for the larger donation. Hope this helped :)
3 the radius of both bases are the sams
I think the answer is 6 since u multiply them
36 × 0.07 = $2.52 sales tax
Answer:
Using either method, we obtain: ![t^\frac{3}{8}](https://tex.z-dn.net/?f=t%5E%5Cfrac%7B3%7D%7B8%7D)
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: ![\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B11%7D%20u%5E%5Cfrac%7B3%2B8%7D%7B8%7D%20%3D%5Cfrac%7B8%7D%7B11%7D%20u%5E%5Cfrac%7B11%7D%7B8%7D)
which evaluated between the limits of integration gives:
![\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B11%7D%20t%5E%5Cfrac%7B11%7D%7B8%7D-%5Cfrac%7B8%7D%7B11%7D%200%5E%5Cfrac%7B11%7D%7B8%7D%3D%5Cfrac%7B8%7D%7B11%7D%20t%5E%5Cfrac%7B11%7D%7B8%7D)
and now the derivative of this expression with respect to "t" is:
![\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%28%5Cfrac%7B8%7D%7B11%7D%20t%5E%5Cfrac%7B11%7D%7B8%7D%29%3D%5Cfrac%7B8%7D%7B11%7D%5C%2C%2A%5C%2C%5Cfrac%7B11%7D%7B8%7D%5C%2Ct%5E%5Cfrac%7B3%7D%7B8%7D%3Dt%5E%5Cfrac%7B3%7D%7B8%7D)
b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then
![g(x)=\int\limits^x_a {f(t)} \, dt](https://tex.z-dn.net/?f=g%28x%29%3D%5Cint%5Climits%5Ex_a%20%7Bf%28t%29%7D%20%5C%2C%20dt)
is continuous on [a,b], differentiable on (a,b) and ![g'(x)=f(x)](https://tex.z-dn.net/?f=g%27%28x%29%3Df%28x%29)
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:
![\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7Bu%5E%5Cfrac%7B3%7D%7B8%7D%20%7D%20%7D%20%5C%2C%20du%3Dt%5E%5Cfrac%7B3%7D%7B8%7D)