Raettttttrrrrrrrrrrrrrrrr
If we assume the hypotenuse is of side length 5:
a^2+b^2=c^2
3^2+b^2=5^2
9+b^2=25
b^2=16
b=4
If the hypotenuse is the unknown:
a^2+b^2=c^2
3^2+5^2=c^2
9+25=c^2
c^2=34
c=(34)^(1/2)
Y=x^2
y=1/3(x+4)^2-9
Hope this helps
Alll angles in a quadrilateral add to 360
so
missing angle=x
108+99+78+x=360
285+x=360
minus 285 from both sides
x=75
missing angle is 75 degrees
That would be 106.5 degrees
