Ask question

Ask question

All categories

2 years ago

10

Assume body weight and height are related by the formula W=2H+13, where W represents weight in pounds and H represents height in

inches. What is the weight in pounds of a person whose height is 5 feet 6 inches?

1 answer:

yulyashka [42]2 years ago

8 0

Given the equqation
W = 2H + 13
where
W is the weight in lb
H is the height in inches

If the height of a person is 5 ft 6 in, we must first convert it to inches. So,
H = 5(12) + 6
H = 66 in

The body weight then is,
W = 2(66) + 13
W = 145 lbs

You might be interested in

Use signed numbers to solve. A helicopter descended 1200 feet, rose 800 feet, and then descended 450 feet. What was the net gain

sergey [27]

The rise or an increase in altitude is represented by positive sign and a decend or decrease in altitude is represented by negative sign.

First the helicopter descended 1200 feet. So the change in altitude will be -1200 feet.

Then the helicopter rose by 800 feet. So the change in altitude will be 800 feet.

Finally the helicopter descended by 450 feet. So the change in altitude will be -450 feet.

The net change in altitude will be the sum of all the above 3 changes.
Change in altitude = -1200 + 800 - 450 = -850 feet

The negative sign indicates a descend i.e. loss in altitude. So the net change in altitude was a loss of 850 feet.

3 0

3 years ago

Consider the function f(x)= (x+4)(x-2) what is the equation of the axis of symmetry

almond37 [142]

if we zero out f(x), namely make y = 0, we can get the roots or x-intercepts for this quadratic equation

$\bf 0 = (x+4)(x-2)\implies \begin{cases} 0=x+4\implies &-4=x\\ 0=x-2\implies &2=x \end{cases}$

now, the equation is in x-terms, meaning is a vertically opening parabola, so the axis of symmetry will be x = something, a vertical line.

well, we have two x-intercepts, one at -4 and another at 2, and the vertex is right half-way between those guys

-4------------(-1)------------2

so the vertex is at x=-1, namely the axis of symmetry is x = -1.

8 0

2 years ago

SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS

antiseptic1488 [7]

Answer:

$\sf -11+7\sqrt{2}$

Step-by-step explanation:

Given expression:

$\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }$

Rewrite 32 as 16 · 2:

$\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }$

Apply radical rule $\sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}$

$\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }$

As $\sf \sqrt{16}=4$ :

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }$

Multiply by the conjugate:

$\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }$

$\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}$

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}$

As $\sf \sqrt{2}\sqrt{2}=\sqrt{4}=2$ :

$\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}$

$\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}$

$\sf \implies \dfrac{11-7\sqrt{2}}{-1}$

$\sf \implies -11+7\sqrt{2}$

7 0

1 year ago

What is the volume of a sphere that has a radius of 6

Leya [2.2K]

Answer:288pi

Step-by-step explanation:4/3pir^3 6^3*4/3*pi 216*4/3*pi 288pi

8 0

2 years ago

Read 2 more answers

2. Find the volume of the prism. Round to the nearest tenth.

natita [175]

$\huge\mathcal\pink{ANSWER}$

$\mathsf \purple{ v = \frac{1}{2} (a + b) \times h \times l}$

$\mathsf \pink{v = \frac{1}{2} (5 + 12) \times 6.1 \times 16}$

$\mathsf \purple{v = \frac{1}{2} (17) \times 6.1 \times 16}$

$\mathsf \pink{v = 8 \frac{1}{2} \times 6.1 \times 16}$

$\mathsf \purple{v = 829.6 {mi}^{3} }$

7 0

2 years ago