<h3>
Answer: 72 people total</h3>
45 boys, 27 girls
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Explanation:
g = number of girls
g+18 = number of boys, since there are 18 more boys than girls
For example, if g = 7, then g+18 = 7+18 = 25. In this example, we have 7 girls and 25 boys. The problem with this example is the ratio of boys to girls is 25:7 which is not equal to 5:3
We could use trial and error until we land on the solution, or we can use algebra as shown in the next section.
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The ratio of boys to girls is 5:3, meaning
(number of boys)/(number of girls) = 5/3
which turns into
(g+18)/g = 5/3
after we make the proper substitutions
Let's solve for g
(g+18)/g = 5/3
3(g+18) = 5g
3g+54 = 5g
54 = 5g-3g
54 = 2g
2g = 54
g = 54/2
g = 27
There are 27 girls.
This leads to,
g+18 = 27+18 = 45
So there are 45 boys
In total, we have 27+45 = 72 people
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Checking the answer:
The claim is that 45/27 is the same as 5/3
For now assume that claim is true. Set the fractions equal to each other and use cross multiplication like so
45/27 = 5/3
45*3 = 27*5
135 = 135
The third equation has the same thing on both sides, so it's a true equation. This must mean the first equation is true as well. Therefore, 45:27 and 5:3 are the same ratio and the answer is confirmed.
You could also use your calculator to note that
45/27 = 1.667
5/3 = 1.667
both decimal values are approximate.
J=john
m=mary
j is 2 times as old as mary
j=2 times m
sum is 21
m+j=21
find mary
subsitute
j=2m therefor subsitute 2m for j
m+2m=21
add like terms
3m=21
divide by 3
m=7
mary=7
*HOPE I HELPED!*
A(n)=ar^(n-1) and we can find the rate upon using the ratio of two points...
50/1250=1250r^2/1250r^0
1/25=r^2
r=1/5 so
a(n)=1250(1/5)^1=250
...
You could have also found the geometric mean which is actually quite efficient too...
The geometric mean is equal to the product of a set of elements raised to the 1/n the power where n is the number of multiplicands...in this case:
gm=(1250*50)^(1/2)=250
Answer:
10 more than fraction 1 over 4 of the sum of 5 and 3, then subtract 3
Step-by-step explanation:
Can't be the other ones
First, try multiplying multiple numbers to see if you get these numbers.
2=4,6,8,10,12,14,16,18,20,22,24,26,(28),30,32,34,36,38,40,(42)
7=7,14,21,(28),35,(42)
14= 14,(28),(42)
14, would be best; Alternatively, the GCF of 28 and 42 can be found using the prime factorization of 28 and 42.
<span>-The factors of 28 are 28, 14, 7, 4, 2, 1.<span>
-The factors of 42 are 42, 21, 14, 7, 6, 3, 2, 1.
Common numbers: 1 , 2, 7,14 , the largest number that can go into both is 14.
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