Answer:
Step-by-step explanation:
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
It is 3 and 1/14ft or 3 and 4/16 ft taller
Answer:
3780
Step-by-step explanation:
84 = 2^2 * 3 * 7
27 = 3^3
35 = 5 * 7
45 = 3^2 * 5
lcm = 2^2 * 3^3 * 5 * 7 = 3780
3x^2+12x+15=0
Then divide by 3 to get the x by itself.
x^2+4x+5=0
Factor to (x+5) (x-1) and solve for the two values of x.