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zloy xaker [14]
3 years ago
6

Daniel wants to save money. The ratio of the amount of money in his savings account to the amount of money in his checking accou

nt was 1:6. Because Daniel is trying to get better at saving money, he moves money out of his checking account and into his savings account. Now the ratio of the amount of money in his savings account to the amount of money in his checking account is 4:3. If Daniel had $936 in his checking account before moving money, how much money does he have in each account after moving money?
Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0
1










.........................
Serhud [2]3 years ago
4 0

Answer:

1

Step-by-step explanation:

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I believe that 30.5 as a fraction is 30 and 1 half but don't take my word
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Suppose you invest $63 a month in an annuity that earns a 3.3% APR
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Answer: $3227.93 APEX

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Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
Write a relationship for a function whose k(x) values are 5 more than four times the principal square root of x .
bearhunter [10]

Answer:

k(x)=5+4\sqrt{x}

Step-by-step explanation:

Write a function whose k(x) values are 5 more than four times the principal square root of x.

So,

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four times the principal square root of x =4\sqrt{x};

5 more than four times the principal square root of x =5+4\sqrt{x};

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k(x)=5+4\sqrt{x}

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Answer this quick please
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Answer:

84s^{2} t\sqrt{35st}

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Read 2 more answers
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