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igomit [66]
3 years ago
7

HELP IS NEED QUICKLY I WILL GIVE BRAINLIEST

Mathematics
2 answers:
lord [1]3 years ago
5 0

Answer:

add $9.99 and $0.35 and get $10.34 and add up to 5 to 6 toppings.

Step-by-step explanation:

nuthin' to see here Bv

Alex Ar [27]3 years ago
3 0

Answer:

Well add the first numbers and get 10.34 you can add up to  at least 5 to 6 toppings.

Step-by-step explanation:

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Is pi ever end. Please answer asap
givi [52]

Answer:

pi will never end just trust me :p

Step-by-step explanation:

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3 years ago
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How to solve this problem 29+12(4)
OLga [1]
The answer is 77 since you would use PEMDAS and multiply 12 * 4 first to receive 48 which then adding a 29 to the 48 resulting in 77 
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3 years ago
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How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
Which linear inequality is represented by the graph?<br> 0214<br> Qys<br> ovas<br> 2x + 3
Luba_88 [7]

Answer:

sorry I just needed points

Step-by-step explanation:

dndjdjdnsnsnsuxknsdu djdjebheu suss hsshsb yshebejdb usjsne

8 0
3 years ago
Write a rule for the following graph
djyliett [7]

Answer:

y = x + 1

Step-by-step explanation:

This is in slope intercept form. 1 is the point that you start at: (0, 1)

The slope is 1

y = 1x + 1 or

y = x + 1

7 0
2 years ago
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