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4vir4ik [10]
2 years ago
9

Help will give brainliest !!! PLEASE ITS EASY

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
3 0

Answer:

5x+19=6x+1

5x+18=6x

18=x

x=18

Hope This Helps!!!

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What is the slope of a line perpendicular to the line whose equation is
jonny [76]

Answer:

- \frac{1}{2}

Step-by-step explanation:

How do we find the line that's perpendicular to another?

We find the negative reciprocal. So for example if our slope is 2, the negative reciprocal would be - \frac{1}{2}.

3 0
3 years ago
David's dinner cost $24. He wants to leave a 20% tip. The tax rate is 8%. What is the total he will pay? (not $31.10)
Hitman42 [59]

Answer:

$30.72

Step-by-step explanation:

You were right with your answer, the teacher is probably just wanting you to tip on the subtotal (before tax) instead of the total total. Instead of doing total+tax+tip, we're going to figure out the tax and tip separately and then add it all together.

<u>Tipping on the subtotal (what your teacher wanted)</u>

20% of $24 = $4.80

8% of $24 = $1.92

$24+$4.80+$1.92=$30.72

<u>Tipping on the total (what you did)</u>

8% of $24 is $1.92

New total is $25.92

20% of $25.92 is $5.18

$25.92 + $5.18 = $31.10

5 0
2 years ago
Solve the system by elimination <br> 2x+6y= -12 <br> 5x-5y= -10
kvv77 [185]
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

5 0
3 years ago
Read 2 more answers
An unknown number y is 15 more than an unknown number x. The number y is also x less than 8. The equations to find x and y are s
melomori [17]
Add the equations to eliminate x
6 0
3 years ago
Read 2 more answers
You use a line of best fit for a set of data to make a prediction about an unknown value. the correlation coeffecient is -0.833
alina1380 [7]

Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

5 0
3 years ago
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