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saul85 [17]
4 years ago
11

How many kilometers are in 5 miles

Mathematics
2 answers:
netineya [11]4 years ago
4 0
Multipli by 0.61 to get your awnser
anzhelika [568]4 years ago
3 0
There are 8.04672 for 5 kilo. by length <span />
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Write the inverse of f(x) = 3^x - 1
NeTakaya

The inverse of this function would be f(x) = \frac{Log(x - 1)}{Log3}.


You can find the value of any inverse function by switching the f(x) and the x value. Then you can solve for the new f(x) value. The end result will be your new inverse function. The step-by-step process is below.


f(x) = 3^{x} - 1 ----> Switch f(x) and x


x = 3^{f(x)} - 1 ----> Add 1 to both sides


x + 1 = 3^{f(x)} -----> Take the logarithm of both sides in order to get the f(x) out of the exponent


Log(x + 1) = f(x)Log3 ----> Now divide both sides by Log3


\frac{Log(x - 1)}{Log3} = f(x) ----> And switch the order for formatting purposes.


f(x) = \frac{Log(x - 1)}{Log3}


And that would be your new inverse function.

8 0
4 years ago
To decrease an amount by 28% , multiply by ????
melomori [17]
I believe it is by .28. you take the original number, multiply if by .28 and subtract that answer from the original answer to decrease the amount by 28%.
5 0
3 years ago
Solve for p2. p1v1 = p2v2
lukranit [14]

Answer:

P₂  = \frac{P_{1} V_{1}  }{V_{2} }  

Step-by-step explanation:

Given expression:

     Boyle's law:

             P₁ V₁   = P₂ V₂

Problem is to find P₂;

Solution:

              P₁ V₁   = P₂ V₂

 To solve this problem, multiply both sides by \frac{1}{V_{2} };

         

   P₁ V₁  x   \frac{1}{V_{2} }; = P₂ V₂  x  \frac{1}{V_{2} };

     \frac{1}{V_{2} } cancels out V₂ on the right hand side;

              P₂  = \frac{P_{1} V_{1}  }{V_{2} }  

6 0
3 years ago
Find the equation of the circle that has a diameter with endpoints located at (-5,-3) and (-11,-3)
zvonat [6]
x^{2} + y^{2} = r^{2}
Radius;
\sqrt{(-5--11)^{2} + (-3--3)^{2}
x^{2} + r^{2} =36

4 0
3 years ago
How many pt are there in 10 qt
nataly862011 [7]
The answer is 20 pt. Hope this helped
8 0
4 years ago
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