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Alekssandra [29.7K]
3 years ago
13

Help no links!!!!!!!!!!!!!!

Mathematics
1 answer:
Softa [21]3 years ago
8 0

Answer:

7.

A.) -⅔

B.) 3/-2

Step-by-step explanation:

from 1 to -1 you have to go down 2

from 2 to -1 you have to go down 3

therefore your slope is -⅔

from 3 to 6 you go up by 3

from 1 to -1 you go down by 2

therefore your slope is 3/-2

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Graph the data from the tables onto the following graph. Note that for both tables, the values in the first column must be plott
DENIUS [597]

Graphs are used to visualize the set of data on a table or functions and equations

<h3>How to graph the table?</h3>

The table is not given.

So, I will make use of the following table to plot the graph

x     y

1       2

2      4

3      6

4      8

5     10

To plot the table on a graph, we place the x values on the x-axis, and the y values on the y-axis

See attachment for the graph of the table

Read more about graphs and tables at:

brainly.com/question/14323743

5 0
3 years ago
If m // n and n // o and p is a transversal, find the
MakcuM [25]

Answer:

See below.

Step-by-step explanation:

Here is one pair of angle of each type. There are more correct answers.

corresponding angles: <K, <O

alternate interior angles: <N, <P

alternate exterior angles: <I, <S

same-side interior angles: <N, <Q

vertical angles: <P, <R

supplementary angles: <J, <M

8 0
3 years ago
A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
4 years ago
Mr. Wing is purchasing a new computer that costs $2,376. There is no interest charge if it is paid for in the next 12 months. Ho
Vedmedyk [2.9K]

Answer: $198

Step-by-step explanation:

2376/12 = 198

6 0
3 years ago
Read 2 more answers
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
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