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3 years ago

12

How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

1 answer:

lidiya [134]3 years ago

8 0

Q. How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

Solution:

Here we are given with the sides of the triangle as 5m, 16m and 5.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here.

Hence no triangle can be made.

So the correct option is None.

Q.How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?

Solution:

Here we are given with the sides of the triangle as 6m, 2m and 7m.

As the Triangle inequality we know that

The sum of the length of the two sides should be greater than the length of the third side. The given values follows the triangle inequality.

Hence one triangle can be formed.

So the correct option is one.

You might be interested in

Rock concert tickets are sold at a ticket counter. Femalesandmalesarriveat times of independent Poisson processes with rates 30

mestny [16]

Answer: The probability that the first three customers are female is 0.216

Step-by-step explanation:

The attachment below shows the calculations clearly.

7 0

4 years ago

Gavin and Jim win some money and share it in the ratio 5:2. Gavin gets £39 more than Jim. How much did they get altogether?

gregori [183]

Answer:

Altogether Gavin and Jim won £95.

Step-by-step explanation:

We are given the following in the question:

Ratio of money won by Gavin and Jim = 5:2

Gavin gets £39 more than Jim.

Let x be the amount of money Won by Jim.

Then, money won by Gavin =

$=(x+39)$

Thus, we can write the equation:

$\dfrac{\text{Gavin}}{\text{Jim}} = \dfrac{5}{2}=\dfrac{x+39}{x}$

Solving, we get,

$\dfrac{5}{2}=\dfrac{x+39}{x}\\\\5x = 2x + 78\\\Rightarrow 3x = 78\\\Rightarrow x = 26\\\Rightarrow (x+39) = 65$

Thus, Gavin won £65 and Jim won £26.

Money won altogether =

$=65 + 26\\=95$

Thus, altogether Gavin and Jim won £95.

5 0

3 years ago

The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100

Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, $\mu$ = 310/1000 or 0.31 and Standard deviation, $\sigma$ = 14.63/1000 = 0.01463 .

We know that Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

P(X <=0.13) = P( $\frac{X-\mu}{\sigma}$ <= $\frac{0.13-0.31}{0.01463}$ ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

4 0

4 years ago

Please I really need help with these two please

Aleks04 [339]

Answer:

I NEED A BIT MORE DETAILS

4 0

4 years ago

What is the equation of the line that passes through the point (1,0) and is perpendicular to the line x+5y=30

Andre45 [30]

Answer:

The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0

Step-by-step explanation:

Given equation of line as

x + 5 y = 30

Now, equation of line in standard form is y = m x + c

where m is the slope

So, x + 5 y = 30

Or, 5 y = - x + 30

Or, y = - $\frac{1}{5}$ x + 6

So, Slope of this line m = - $\frac{1}{5}$

Again , let the slope of other line passing through point (1 , 0) is M

And Both lines are perpendicular , So , products of line = - 1

i.e m × M = - 1

Or, M = - $\frac{1}{m}$

Or, M = - 1 × - $\frac{1}{\frac{1}{5}}$ = $\frac{1}{5}$

So, equation of line with slope M and points (1, 0) is

y - $y_1$ = M × (x - $x_1$ )

Or, y - ( 0 ) = $\frac{1}{5}$ × ( x - 1 )

Or, y = $\frac{1}{5}$ x - $\frac{1}{5}$ × 1

Or, y = $\frac{1}{5}$ x - $\frac{1}{5}$

or, y + $\frac{1}{5}$ = $\frac{1}{5}$ x

Or, 5×y + 1 = x

∴ 5 y + 1 = x

I.e x - 5 y - 1 = 0

Hence The equation of line passing through points (1 , 0) is x - 5 y - 1 = 0 Answer

7 0

3 years ago