Answer:
I can’t give you the answer but there this google app
Step-by-step explanation:
Called algebratiger
N(2n+6)-(n²-1)= 2n²+6n-n²+1=n²+6n+1
Answer:
A
Step-by-step explanation:
He needs to collect at least 120 so if c is what he must still collect
64 +c must be greater than or equal to 120
What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.

so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2