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3 years ago

Please tell me b. Do not want to think right now. Thanks.

Mathematics

1 answer:

Julli [10]3 years ago

6 0

Answer:

sorry man i dont know what that means

Step-by-step explanation:

You might be interested in

You have at most 30 games on your smartphone. Write an inequality that represents this situation.

serious [3.7K]

Answer:

30 ≥ x

Step-by-step explanation:

4 0

3 years ago

Will mark as Brainliest.

Flauer [41]

The answer is b, which reads:
the log of 1024, base 4, is x

3 0

3 years ago

Use the rational zero theorem to create a list of all possible rational zeros of the function f(x)=14x7-4x2+2

frosja888 [35]

Answer:

Factor this polynomial:

F(x)=x^3-x^2-4x+4

Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).

The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at

x = 1, x = 2 and x = -2. This means that

x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)

A = 1, as you can see from equation the coefficient of x^3 on both sides.

Typo:

The rational roots can be

+/-1, +/-2 and +/-4

Step-by-step explanation:

6 0

3 years ago

Find S9, the sum of the geometric series to the 9th term, in which a3=3.645 and a8=15

ArbitrLikvidat [17]

Answer:

The sum of the first nine terms of the sequence is 74.44.

Step-by-step explanation:

Geometric sequence concepts:

The nth term of a geometric sequence is given by the following equation.

$a_{n+1} = ra_{n}$

In which r is the common ratio.

This can be expanded for the nth term in the following way:

$a_{n} = a_{1}r^{n-1}$

In which $a_{1}$ is the first term.

Or even:

$a_{n} = a_{m}r^{n-m}$

The sum of the first n terms of a geometric sequence is given by:

$S_{n} = \frac{a_{1}(1 - r^{n})}{1 - r}$

Finding the common ratio:

$a_{3} = 3.645, a_{8} = 15$

$a_{n} = a_{m}r^{n-m}$

$a_{8} = a_{3}r^{8-3}$

$a_{3}r^{5} = a_{8}$

$3.645r^{5} = 15$

$r^{5} = \frac{15}{3.645}$

$r = \sqrt[5]{\frac{15}{3.645}}$

$r = 1.327$

Finding the first term:

$a_{3} = a_{1}r^{2}$

$a_{1} = \frac{a_{3}}{r^{2}}$

$a_{1} = \frac{3.645}{(1.327)^{2}}$

$a_{1} = 2.07$

Sum of the first nine terms:

$S_{9} = \frac{2.07*(1 - (1.327)^{9})}{1 - 1.327} = 74.44$

The sum of the first nine terms of the sequence is 74.44.

8 0

3 years ago

Read 2 more answers

Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,

Kazeer [188]

Answer: 2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula $A=A_oe^{kt}$ where

A is the final amount (amount left)
A₀ is the initial amount (amount you started with)
k is the rate of decay (you need to solve for this)
t is the time

Given:

A = 1/2(300) = 150
A₀ = 300
k = unknown
t = 28.8

$150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\$

Next, input the k-value and the new t-value to solve for A.

A = unknown
A₀ = 300
k = -0.0240676
t = 1440

$A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\$

5 0

4 years ago