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Rom4ik [11]
3 years ago
12

What are the possible values of x for the following functions?

Mathematics
1 answer:
stiks02 [169]3 years ago
7 0
What can a denominator never be?

0

so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.

so, what x values make our denominator 0?

to figure this out, we need to set (x-1)(x-2)=0

now we split and solve.

x - 1 = 0 \\ x - 2 = 0
so when x is 1 or 2 the function doesnt make sense.

but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
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Answer:

666

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6 0
3 years ago
Read 2 more answers
Simplify.<br><br> 42+25<br><br><br><br> A.21<br><br> B.29<br><br> C.41<br><br> D.51
bearhunter [10]

Im actually pretty sure its C because 4 to the power of 2 is 16 and then add those too up 16+25=41

8 0
3 years ago
Tammy scored 88, 72, 44 points on her first three test. What must she score in her last test to get at least an average of 70?
lara [203]

Answer:

76

Step-by-step explanation:

(88+72+44+x)/4=70

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204+x=280

x=76

Therefore, Tammy needs to score a 76 on her last test to get at least an average of 70.

5 0
3 years ago
1. x + 2x - 1 = 38<br> Inverse operation
Lena [83]

Answer:

x=13

Step-by-step explanation:

First, you add the x's together: 2x+x=3x

Now you have:3x-1=38

Add 1 to both sides: 3x=39

1 cancel on the left side of the equation

Divide 3 on both sides: x=39/3

3 cancels on the left side and 39 divided by 3 is 13:

x=13

Hope this helps!

6 0
3 years ago
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