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Mice21 [21]
3 years ago
10

I need help on 3and 5 PLS ASAP

Mathematics
1 answer:
AnnZ [28]3 years ago
7 0

The 3rd answer is about 1 and the 5th one is about 3 hours

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◕ A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer. The retailer added transportation cost of Rs 250 , pr
satela [25.4K]

<u>Given </u><u>:</u><u>-</u>

  • A dealer sold a photocopy machine at Rs 4200 with 13% VAT to a retailer.
  • The retailer added transportation cost of Rs 250 , profit Rs 300 and local tax Rs 150 and sold to consumer .
  • Customer has to pay 13% VAT .

<u>To </u><u>Find </u><u>:</u><u>-</u>

  • Amount to be paid by the customer .

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u>

Here , according to the question ,

\sf\dashrightarrow Cost\ of \ machine \ = \ Rs 4200

\sf\dashrightarrow VAT = 13\%

Therefore cost after adding VAT ,

\sf\dashrightarrow Cost = Cost_{initial}+13\% of Cost_{initial}\\

\sf\dashrightarrow Cost = Rs4200 + Rs 4200 \times \dfrac{13}{100}\\

\sf\dashrightarrow Cost = Rs4200 + Rs546\\

\sf\dashrightarrow \bf{ Cost = Rs 4746}

Again the values added by the retailer before selling to customer ,

  • Transport = Rs 250
  • Profit = Rs 300
  • Tax = Rs 150

Therefore total cost after adding these ,

\sf\dashrightarrow Cost = Rs( 4746+ 250+ 300 + 150 )\\

\sf\dashrightarrow\bf { Cost = Rs 5446}

Again Selling price after addition of 13% VAT ,

\sf\dashrightarrow SP = Rs 5446 + 13\% \ of \ Rs 5446\\

\sf\dashrightarrow SP = Rs 5446 + \dfrac{13}{100}\times 5446 \\

\sf\dashrightarrow SP = Rs (5446 + 707.98) =  Rs ( 5446 + 708)\\

\sf\dashrightarrow \underline{\underline{\bf SP_{to\ the \ customer} = Rs 6154}}

<u>Hence </u><u>the </u><u>amount </u><u>to </u><u>be </u><u>paid </u><u>by </u><u>the </u><u>customer </u><u>is </u><u>Rs </u><u>6</u><u>1</u><u>5</u><u>4</u><u> </u><u>.</u>

3 0
2 years ago
Read 2 more answers
1. Nikola invested $6.000 in a 3 year
Kamila [148]
I would rather say A or C
3 0
3 years ago
Solve for x: 3(x + 1) = −2(x − 1) − 4
Anika [276]
Solve your equation step-by-step.

3(x+1)=−2(x−1)−4


Simplify both sides of the equation.

3(x+1)=−2(x−1)−4

Simplify:

3x+3=−2x−2

Add 2x to both sides.

3x+3+2x=−2x−2+2x

5x+3=−2

Subtract 3 from both sides.

5x+3−3=−2−3

5x=−5

Divide both sides by 5.

5x/5 = −5/5

x=−1


4 0
3 years ago
How many 4X4in squares will i need to cover 20ft high 10 ft wide wall
IRINA_888 [86]
Find the area of the squares.
4 ×4 = 16

Find the area of the wall.
20 × 10 =200

Divide 200 by 16.
200 ÷ 16 = 12.5

You need 12.5 squares.
8 0
3 years ago
I have assessment quiz please
alekssr [168]

Answer:

A&B

....

...

....

.......

.....

7 0
2 years ago
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