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Gre4nikov [31]
2 years ago
8

A circle with a radius of 5 has a sector with a central angle of 9/10pi radians what is the area of the sector

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
6 0

Answer:

11.25pi units² or 35.3 units² (3 sf)

Step-by-step explanation:

½×r²×theta

½ × 5² × 0.9pi

11.25pi units²

Or, 35.3 units² (3 sf)

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Pythagorean Theorem to solve for x. If the hypnoses is 10 m, and one leg is 6 m. Find the other leg x
lilavasa [31]

Answer:

The other leg X = 8m

Step-by-step explanation:

As per Pythagorean theorem-

Square of hypotenuse = sum of square of other two sides  of the triangle

Substituting the given values in above equation, we get -

10^2 = 6^2 + X^2\\100 - 36 = X^2\\X^2 = 64\\X = 8m

The other leg X = 8m

8 0
2 years ago
PLS HELP ASAP ILL GIVE BRAINLY
My name is Ann [436]

Answer:

It’s nonlinear because you can’t put x by itself

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
William works at a nearby electronics store. He makes a commission of 6% on everything he sells. If he sells a computer for$764.
Sedaia [141]
Commission=0.06×764=$45.84
7 0
3 years ago
Identify the x-intercept and y-intercept of the equation below.
Lady_Fox [76]
Divide by 21 to put the equation in intercept form.
  x/(21/9) + y/(-21/7) = 1
  x/(7/3) + y/(-3) = 1

The x-intercept is (7/3, 0)
The y-intercept is (0, -3)

The 3rd choice is appropriate.

8 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
2 years ago
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