A circle with a radius of 5 has a sector with a central angle of 9/10pi radians what is the area of the sector

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

6 0

Answer:

11.25pi units² or 35.3 units² (3 sf)

Step-by-step explanation:

½×r²×theta

½ × 5² × 0.9pi

11.25pi units²

Or, 35.3 units² (3 sf)

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Question #19- Use the answer bank below to fill in missing parts of the proof.

serious [3.7K]

Answer:

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Step-by-step explanation:

$\overline{PQ}\cong \overline{PR}$ : Reason; Given

Draw $\overline{PM}$ so that M is the midpoint of $\overline{QR}$ : Reason; Two points determine a line

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andrey2020 [161]

$\bf x^4+xy^3+x^3+y^3\impliedby \textit{now let's do some grouping}
\\\\\\
(x^4+xy^3)~~+~~(x^3+y^3)\implies x(x^3+y^3)~~+~~(x^3+y^3)
\\\\\\
\stackrel{\stackrel{common}{factor}}{(x^3+y^3)}(x+1)\\\\
-------------------------------\\\\
\textit{now recall that }\qquad \qquad \textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
a^3-b^3 = (a-b)(a^2+ab+b^2)\\\\
-------------------------------\\\\
(x+y)(x^2-xy+y^2)(x+1)$