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Ugo [173]
2 years ago
10

Need help with these two questions please

Mathematics
1 answer:
lisabon 2012 [21]2 years ago
4 0
You can figure out the answer by doing this:

8% = 2300/x 

and do the same for the second one
(and solve)
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What is the k?<br> 5/k = 15/20
myrzilka [38]

Answer:

Step-by-step explanation:

k=15/20*5

k= 75/20 or 3.75

fraction can also be  15/4 or 3 3/4

5 0
3 years ago
Figure FGHJ is shown below.
Mumz [18]

Answer:

quadilateral and parallelogram

Step-by-step explanation:

Find the diagram attached.

The given four is known to have 4 sides and sicne quadilaterals are figures having four side, hence the given figure is a quadilateral. The example of the quadilateral is a parallelogram since opposite sides of the quadilateral are equal.

The names that accurately descbes the figure are quadilateral and parallelogram

3 0
2 years ago
Read 2 more answers
Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?
ANTONII [103]

Answer:

answer is first option

{x}^{2}  -3x - 5 = 0

wherein, a = 1, b = -3, c = -5

8 0
3 years ago
Read 2 more answers
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
3 years ago
Two integers a and b have a product of -33. What is the least possible sum of a and b
irga5000 [103]

 

The number -33 divisors are:

D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}

a × b = -33

<u>1)  -33 × 1 = -33   ⇒   Sum is:   -33 + 1 = -32</u>

2)  -11 × 3 = -33   ⇒   Sum is:   -11 + 3 = -8

3)  -3 × 11 = -33   ⇒   Sum is:   -3 + 11 = 8

4)  -1 × 33 = -33   ⇒   Sum is:   -1 + 33 = 32

<u>5)  1 × (-33) = -33   ⇒   Sum is:   1 + (-33) = 1 - 33 = -32</u>

6)  3 × (-11) = -33   ⇒   Sum is:   3 + (-11) = 3 - 11 = -8

7)  11 × (-3) = -33   ⇒   Sum is:   11 + (-3) = 11 - 3 = 8

8)  33 × (-1) = -33   ⇒   Sum is:   33 + (-1) = 33 - 1 = 32

<h2>The least possible sum of a and b is  -32</h2>

to 1)  and to 5)



7 0
3 years ago
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