Answer:
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
Set up equation before taxes.
y = x - 1500 eq1
Set up equation for total tax paid.
0.065x + 0.06y = 378.75 eq2
Substitute eq1 into eq2.
0.065x + 0.06(x - 1500) = 378.75
0.065x + 0.06x - 90 = 378.75
0.125x - 90 = 378.75
0.125x = 468.75
x = 3750
Substitute this value of x into eq1.
y = 3750 - 1500
y = 2250
The hotel charge in city one is $3750 and the hotel charge in city two is $2250
Answer:
(9,12)
Step-by-step explanation:
Present area = 120 * 80 = 9600 ft^2 so the new area will be 9600 + 4400 = 14000
So if increase in length = x we have
(x + 120)(x + 80) = 14,000
x^2 + 200x + 9600 - 14000 = 0
x^2 + 200x - 4400 = 0
x = 20 feet answer
-120 + 13m, at time m = 6, would be -120 + 78, or -42 feet.
Step-by-step explanation:
f'(x) is usually used in calculus to denote the first derivative of f(x) so f'(2) will simply be the first derivative of f(2).
f(x)=x+3
f'(x)=1
thus x does affect the first derivative and your answer for f'(x)=1
