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Sunny_sXe [5.5K]
3 years ago
12

Point A is on circle O. Which statement is NOT true? * A. There are many tangent lines that contain point A. B. There is exactly

one diameter that contains point A. C. There are many chords of the circle that contain point A. D. Segment OA is a radius of the circle.
Mathematics
1 answer:
miss Akunina [59]3 years ago
4 0

Answer: A. There are many tangent lines that contain point A.

Step-by-step explanation:

Given, Point A is on circle O.

  • A tangent line at a given point is the straight line that touches the curve at that point.
  • A tangent line has to be perpendicular to the radius at this point. And perpendicular lines through a given point are unique.

That means, Statement A. "There are many tangent lines that contain point A" is wrong.

  • Diameter is the line drawn between two points of the circle that passes through the center, so statement B is correct.
  • Chords are lines drawn between any two points of the circle, so statement  C is also correct.
  • Radius is the distance from the center of the circle to its boundary, So statement D is also correct.

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Devaughn is 15 years younger than Sydney. The sum of their ages is 37 . What is Sydney's age?
posledela
Hi,
Let Sydney's age be x.
Devaughn=(x-15)
x+(x-15)=37
x+x-15=37
2x-15=37
2x=37+15
2x=52
x=52/2
x=26
Sydney is 26 years old.
Hope this Helps you.
7 0
3 years ago
Use the slope formula to find the slope of the line passing through the given points.
n200080 [17]

Answer:

The slope is -3

Step-by-step explanation:

We can find the slope using

m = (y2-y1)/(x2-x1)

   = (-5-1)/(4-2)

   = -6/2

    = -3


3 0
3 years ago
A car is traveling down a highway at a constant speed, described by the equation LaTeX: d=65td=65t, where represents the distanc
maks197457 [2]

Answer: The car travels 97.5 miles in 1.5 hour.

Step-by-step explanation:

Given: A car is traveling down a highway at a constant speed, described by the equation , described by the equation d=65t, where represents the distance, in miles, that the car travels at this speed in<em> t</em> hours.

To find : Number of miles car travel in 1.5 hour.

Simply put t= 1.5 in the given expression , we get

65(1.5)= 97.5

That means , the car travels 97.5 miles in 1.5 hour.

7 0
3 years ago
HELP, I AM UTTERLY CONFUSED *20 points
Studentka2010 [4]
Ok so this question is a bit complicated, but it's easier to understand if you break it down into smaller parts!

1) First, you know that ABGF is half the perimeter of ACDE. This means that the length of one side of ABGF must be 1/2 the length of one side of ACDE.
>> You can think of this by putting in random numbers. Say the perimeter of the larger square is 24 and the perimeter of the smaller square is 12. That means one side of the larger square of 24/4 (b/c four sides) = 6 and one side of the smaller square is 12/4 = 3!

2. Ok know you know the lengths of the sides relative to each other, but you're only given one value: 4in. Since the smaller square has sides that are 1/2 the larger squares, you know that it makes up 1/4 of the larger square! So imagine 4 of those smaller squares filling up that larger square to make a 2 by 2. It just so happens that 4in is the diagonal going through one of our imaginary squares, which is equal in size to ABGF!

3. Now use the 45-45-90 rule to figure out the length of one side of that imaginary square because the 4in diagonal splits that imaginary square into two of those 45-45-90 triangles. You know the hypotenuse of that triangle is 4in. That means one of the legs is 4/✓2 (since the rule says that the hypotenuse and the leg are in a ✓2:1 ratio). And like we said before the length of that leg is the length of the side of our imaginary square. And our imaginary square must be the same size as ABGF! So now we know the side of the smaller square to be 4/✓2!

4. Multiply the side of the smaller square by 2 to get the side of our larger square. (4/✓2)*2=8/✓2

5. Now to find the area of the shaded region, just find the area of the smaller square ABGF and subtract from the larger square ACDE. Use equation for the area of a square!
a =  {s}^{2}
where s=the length of one side.

The length of one side of the smaller square is 4/✓2. So it's area is:
{( \frac{4}{ \sqrt{2} }) }^{2}  =  \frac{16}{2}  = 8

The length of one side of the larger square is 8/✓2. So it's area is:
{ ( \frac{8}{ \sqrt{2} }) }^{2}  =   \frac{64}{2}   = 32

Now subtract. 32-8=24! :)

Hope this helps! Let me know if you have any questions.
3 0
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Show that angle a+ angle b is equal to angle d​
mr_godi [17]

sum of two angles of triangle are equal to the exterior angle of triangle

8 0
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