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Zielflug [23.3K]
3 years ago
11

I need to know how to evaluate this question

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
3 0
1.) 2+8*5-1+3
     2 +  ∨     ∨
     2+ 40-1+3
            ∨
         2+ 39
            ∨
            41+3=44. 



3.)  7+3-1-21/7
                 ∨
7  + 3 - 1 -  3
   ∨
 10 - 1- 3
     ∨
    9-3=6. hope that helped.
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Linear System, substitutional method<br><br> 5x+4y=32 <br> 9x-y=33<br><br> helppp
Pachacha [2.7K]
5x + 4y = 32 ⇒ 45x + 36y = 288
9x -  1y = 33 ⇒ <u>45x -    5y = 165</u>
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                                     41      41
                                        y = 3
                            5x + 4(3) = 32
                              5x + 12 = 32
                               <u>    - 12  - 12</u>
                                      <u>5x</u> = <u>20</u>
                                       5      5
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6 0
3 years ago
If y varies inversely as x and y=3 when x=4, then y=12 when x=15 <br><br> True or false ?
Elden [556K]

y=12 is false answer.

8 0
3 years ago
What's the proper name of this quadrilateral?
klemol [59]
Trapezoid because a trapezoid is a quaderateral with 4 sides
4 0
3 years ago
Read 2 more answers
1st. (2 root 2 + root 3 ) ( 2 root 3 - root 2)
satela [25.4K]

Answer:

1st: 3*root6 + 5

2nd: 35*root2 + 115

3rd: 24*root2 - 20*root6 + 15*root3 - 18

4th: 17*root6 - 38

5th: 13*root10 - 42

Step-by-step explanation:

To simplify these expressions we need to use the distributive property:

(a + b) * (c + d) = ac + ad + bc + bd

So simplifying each expression, we have:

1st.

(2 root 2 + root 3 ) ( 2 root 3 - root 2)

= 4*root6 - 2*2 + 2*3 - root6

= 3*root6 - 4 + 9

= 3*root6 + 5

2nd.

(root 5 + 2 root 10) (3 root 5 + root 10)

= 3 * 5 + root50 + 6*root50 + 2*10

= 15 + 5*root2 + 30*root2 + 100

= 35*root2 + 115

3rd.

(4 root 6 - 3 root 3) (2 root 3 - 5)

= 8*root18 - 20*root6 - 6*3 + 15root3

= 24*root2 - 20*root6 + 15*root3 - 18

4rd.

(6 root 3 - 5 root 2 ) (2 root 2 - root 3)

= 12*root6 - 6*3 - 10*2 + 5*root6

= 17*root6 - 18 - 20

= 17*root6 - 38

5th.

(root 10 - 3 ) ( 4 - 3 root 10)

= 4*root10 - 3*10 - 12 + 9*root10

= 13*root10 - 30 - 12

= 13*root10 - 42

8 0
3 years ago
For what real values of does the quadratic 12x^2+k*x+27=0 have nonreal roots
icang [17]

Step-by-step explanation:

Discriminant : k² - 4(12)(27) < 0

So k² - 1296 < 0, -36 < k < 36.

3 0
3 years ago
Read 2 more answers
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