Question

I need to factor 4n^2+4n-3. How??

Answer 1

Simple.....

you have: $4n^{2} +4n-3$

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

If you plug it into the box method you should get...--->>>

(2n-1)(2n+3)

Thus, your answer.