Round to the nearest thousand 706,421

1 answer:

Nutka1998 [239]3 years ago

6 0

The answer is 706,000 because the 4 rounds down and turns into a zero and so does the 2 and the 1. everything else stays the same

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Someone pleaseee help me on this :( what is the slope of the line that contains these points.

Papessa [141]

Answer:

6/1

Step-by-step explanation:

the reason is because the x is increasing by 1 which is the denominator, and the y is also increasing by 6 which is the numerator. if you were to imagine those lines on a graph you would get a straight line and use rise over run to see that the slop is in fact 6/1

8 0

3 years ago

Read 2 more answers

What is the equation of the perpendicular to y=2/3x+1 that passes through the point (12,-6)

postnew [5]

Well, first off let's check what is the slope of y = 2/3x+1.... .hmmmmm, notice $\bf y=\stackrel{slope}{\cfrac{2}{3}}x+1$ , since the equation is already in slope-intercept form, we can see it has a slope of 2/3.

well then, a line perpendicular to that one, will have a negative reciprocal to it.

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{2}{3}\\\\
slope=\cfrac{2}{{{ 3}}}\qquad negative\implies -\cfrac{2}{{{ 3}}}\qquad reciprocal\implies - \cfrac{{{ 3}}}{2}$

so, we're really looking for the equation of a line whose slope is -3/2 and goes through 12, -6.

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 12}}\quad ,&{{ -6}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies -\cfrac{3}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-6)=-\cfrac{3}{2}(x-12)
\\\\\\
y+6=-\cfrac{3}{2}x+18\implies y=-\cfrac{3}{2}x+12$

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3 years ago

Identify the equation that describes the line in slope-intercept form. slope =1; y-intercept =1\3

QveST [7]

Answer: y=x+1/3

Step-by-step explanation:

Y=mx+b form

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3 years ago

Write the equation of the line that passes through the points (2,-6) and (6,-6).

NeTakaya

Answ

Step-by-step explanation:

Two point slope =-(-6+6)/(6-2) =0

Equation is y+6 = 0(x-2)

y+6=0

y=-6

The point is -6 at y axis which is a horizontal line.

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3 years ago

Perform indicated operations for function: f(x)=x^2+1 use in f(x+h)-f(x)/h

8090 [49]

For $f(x+h) - \dfrac{f(x)}{h}$ reading the fraction like f(x)/h only (f(x+h) start fraction f(x) / h end fraction), the answer is $-x^2/y + x^2 + 2x + y + y^2 - 1/y + 1$

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3 years ago