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3 years ago

Which points in the graph are in quadrant IV

Mathematics

2 answers:

Mama L [17]3 years ago

7 0

Quadrant IV is also known as the 4th quadrant. Imagine it like a C: 1st quadrant is in the top right, 2nd quadrant is in the top left, 3rd quadrant is in the bottom left, and the 4th quadrant is in the bottom right. With this information in mind, the answer is A) P, B, K

saw5 [17]3 years ago

5 0

Answer:

Letter B I am sure

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3 years ago

What are the roots of the polynomial equation x3 - 6x = 3x2 - 8? Use a graphing calculator and a system of equations.

makkiz [27]

Answer:

d : 4, 1, -2.

Step-by-step explanation:

There's no need for a calculator in my opinion because we can use the rational root theorem which states that the equations of this form:

$\sum_{i=0}^{n} a_{i}x^i = 0 = a_{0} + a_{1}x + a_2x^2 + ... + a_nx^n = 0\\ a_i \in \mathbb{Z}$

Have rational roots, than the roots are of the form: $\frac{k \cdot a_o}{p \cdot a_n}, \ where \ k, p \in \mathbb{Z}.$

Rewriting the equation we have:

$x^3 - 3x^2 -6x + 8 = 0\\By \ our\ previous \ claim \ x \in D_8 \ where \ D_n \ the \ set \ of \ divisors \ of \ n.\\D_8 = \{\pm 1, \pm 2, \pm 4, \pm 8\} \\We \ plug \ in \ some \ number from \ D_8.\\Letting \ x = -2;\\(-2)^3 -3(-2)^2 -6(-2) + 8 = 0 \ \ \ Thus \ x+2 \ is \ a \ factor.\\We \ can \ now \ simplify \ the \ eq. \ using \ Polynomial \ Long \ Division.$

$x^3 -3x^2 -6x + 8 = (x+2)(Q(x))\\To \ find \ Q \ we \ divide \ the \ original \ equation \ by \ x + 2; which \ yields:\\Q(x) = x^2 - 5x + 4.\\So \ we \ can \ use \ the \ quadratic \ formula \ to \ find \ the \ roots:\\x = 4,x = 1. \\Thus \ x \in \{-2, 1, 4\}. \ \ These \ are \ all \ the \ roots.$

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4 years ago