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3 years ago

If (7,2) is an ordered pair of the function f(x) which of the following must be an ordered pair of the inverse of f(x)?

Mathematics

2 answers:

Harrizon [31]3 years ago

8 0

All you have to do is to reverse the order of the x and y components of (7,2):
(2,7).

leonid [27]3 years ago

4 0

Answer:

(2,7)

Step-by-step explanation:

Here is an example just to show that it works.

3x+2y=25

3(7) + 2(2) = 21 + 4 = 25

3y+2x=25

25-2x=3y

25/3 - 2/3x = y

25/3 -2*2/3=25-4/3=21/3=7

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Please help the answer is not 59 o think

Diano4ka-milaya [45]

Answer:

the answer is 59

Step-by-step explanation:

8 0

3 years ago

Perform the multiplication. Simplify the answers. 2 √30*( √5+ √6+ √10+ √15)

Delicious77 [7]

The simplified expression of $2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$ is $10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

The expression is given as:

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$

Expand the expression

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2\sqrt{30} \times \sqrt5+ 2\sqrt{30} \times \sqrt6+ 2\sqrt{30} \times \sqrt{10} + 2\sqrt{30} \times \sqrt{15}$

Factor out 2

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{30} \times \sqrt5+ \sqrt{30} \times \sqrt6+ \sqrt{30} \times \sqrt{10} + \sqrt{30} \times \sqrt{15})$

Combine the radicals

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{150} + \sqrt{180}+ \sqrt{300} + \sqrt{450})$

Expand the expression

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{25 \times 6} + \sqrt{9 \times 20}+ \sqrt{100 \times 3} + \sqrt{225\times 2})$

Evaluate the roots

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(5\sqrt{6} + 3\sqrt{20}+ 10\sqrt{3} + 15 \sqrt{2})$

Expand

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) =10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

Hence, the simplified expression of $2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$ is $10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

Read more about simplified expressions at:

brainly.com/question/8008182

3 0

2 years ago

A right cylinder has a radius of 2 units and a height of 5 units. What is the volume of the cylinder? Round to the nearest 10th.

NeTakaya

Answer:

62.8 units

Step-by-step explanation:

The formula for a cylinder πr²h. R being the radius and h being the height.

Therefore, plug in the numbers and solve.

π(2)²(5) = 20π = 62.8 units

3 0

3 years ago

Read 2 more answers

What is the fully factored form of 32a^3 + 12a^2?

Klio2033 [76]

<u>Answer:</u>

$4a^{2} (8a + 3)$

<u>Step-by-step explanation:</u>

32a^3 + 12a^2

To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:

32a^3 + 12a^2

a^2 (32a + 12)

Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:

a^2 (32a + 12)

4a^2 (8a + 3)

So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).

7 0

3 years ago

In parallelogram ABCD, what is BDC?

zavuch27 [327]

Answer:

Step-by-step explanation:

<ABD=<BDC

Check it out

5 0

2 years ago

Read 2 more answers