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FinnZ [79.3K]
3 years ago
15

Hypoteneous base and what is the other ​

Mathematics
2 answers:
Yuliya22 [10]3 years ago
7 0

Answer:

Just the hypotenuse and the 2 legs

vivado [14]3 years ago
5 0

Answer:

Perpendicular

Step-by-step explanation:

A right angled triangle have three sides

1) hypotenuse

2) base

3) perpendicular

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I’ll give the Brainliest to whoever answers this question with a reasonable explanation.
SVEN [57.7K]

a) 0-32000
1-30000
2-28000
3-26000
4-24000
b)y=-2000x+32000
c) 16 min

7 0
3 years ago
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
A school pays $1,825 for 150 shirts. This includes the $25 flat-rate shipping cost. What equation models the total cost as a fun
likoan [24]

Answer:

c(t) = 25 +12 * t

where t is the number of shirts

Step-by-step explanation:

The total cost for the shirts  is the flat fee plus the cost per shirt times 150 shirts

total = fee + cost per shirt* shirts

1825 = 25 +c*150  

 where c is the cost per shirt

We need to determine the cost per shirt by subtracting 25 from each side

1825-25 = 150c

1800 =150c

Divide by 150 on each side

1800/150 =150c/150

12 =c

Each shirt costs 12 dollars

We want to make the function in terms of cost per shirt

c(t) = 25 +12 * t

where t is the number of shirts

6 0
3 years ago
How many solutions does this system have? 5y = x - 9 4x - 10y = 18<br><br> plzzz i need answer now
Veseljchak [2.6K]

l o l  

o k

s o

5x=x-9  and 4x-10y=8

lets graph that on desmos cause I'm too lazy to subsitute it .

it has one answer

7 0
3 years ago
PLZZ HELP ME
dimulka [17.4K]

Answer:

125/100 X 105 = 131.25

loan total = $131.25

3 0
2 years ago
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