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Leya [2.2K]
3 years ago
6

Please help me ill give you 10 points

Mathematics
1 answer:
Kitty [74]3 years ago
7 0
C=2pi8
c=16pi or c≈50.27
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1.6y+y-4/15y+1 1/6y=2 1/3
Advocard [28]

<u>1.6y+y-4/15y+7/6y=21/3</u>

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<u>We move all terms to the left:</u>

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<u>1.6y+y-4/15y+7/6y-(21/3)=0</u>

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<u>Domain of the equation: 15y!=0</u>

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<u>y∈R</u>

<u>Domain of the equation: 6y!=0</u>

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<u>y!=0/6</u>

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<u>y∈R</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>1.6y+y-4/15y+7/6y-7=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>2.6y-4/15y+7/6y-7=0</u>

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<u>We calculate fractions</u>

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<u>2.6y+(-24y)/90y^2+105y/90y^2-7=0</u>

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<u>We multiply all the terms by the denominator</u>

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<u>(2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0</u>

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<u>Wy multiply elements</u>

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<u>-630y^2+105y+(+2.6y)*90y^2+(-24y)=0</u>

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<u>We get rid of parentheses</u>

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<u>-630y^2+105y+(+2.6y)*90y^2-24y=0</u>

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<u>We add all the numbers together, and all the variables</u>

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<u>-630y^2+81y+(+2.6y)*90y^2=0</u>

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5 0
3 years ago
where is sandy mistake ive been trying for 30 mintues and still cant find it im not very good at math please help
MArishka [77]

Answer:

Sandy did not follow PEMDAS and added first instead of doing her multiplication and division and then her addition and subtraction the answer would be 18

6 0
3 years ago
What's greater 5.05 or 5.050
Ad libitum [116K]
5.05 = 5.050
So, the numbers 5.05 and 5.050 are equal.
6 0
3 years ago
Point M is located at (4, 6) on a coordinate grid. Point M is translated 8 units to the left and 9 units down to create point M.
weqwewe [10]

Answer:

D

Step-by-step explanation:

You can look at it like a right triangle being made with the vertical part being 9 and the horizontal part being 8, then you want to find the diagonal part. So that's the Pythagorean theorem


\sqrt{8^2+9^2}=12.042

8 0
4 years ago
A company estimates that its cost and revenue can be modeled by the functions C)-0.75x+20,000
lisabon 2012 [21]

Let C(x) = -0.75x + 20,000 and R(x)= -1.50x then the profit function exists noted as P(x) = R(x) - C(x)

P(x) = -1.50x - (-0.75)x + 20,000

P(x)  = -0.75x + 20000

Therefore, the profit function exists -0.75x + 20000.

<h3>How to find profit function?</h3>

The profit function can be estimated by subtracting the cost function from the revenue function. Let profit be expressed as P(x), the revenue as R(x), the cost as C(x), and x as the number of items traded. Then the profit function exists noted as P(x) = R(x) - C(x).

Given:

C(x) = -0.75x+20,000 and R(x)= -1.50x

P(x) = R(x) - C(x)

= -1.50x - (-0.75)x + 20,000

= -1.50x + 0.75x + 20,000

Apply rule -(-a) = a

= -1.5x + 0.75x + 20000

Add similar elements:

-1.5 x + 0.75x = -0.75x

P(x)  = -0.75x + 20000

Therefore, the profit function exists -0.75x + 20000.

To learn more about profit function refer to:

brainly.com/question/16866047

#SPJ9

8 0
2 years ago
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