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Oduvanchick [21]
3 years ago
14

Help need to be done soon​

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0

<u>Given</u>:

Given that the measure of arc DF is 162°

We need to determine the measure of ∠E

<u>Measure of ∠E:</u>

The measure of ∠E can be determined using the inscribed angle theorem.

Thus, by inscribed angle theorem, we have;

\angle E=\frac{1}{2}(m \widehat{DF})

Substituting m \widehat{DF}=162^{\circ}, we get;

\angle E=\frac{1}{2}(162^{\circ})

Dividing, we get;

\angle E=81^{\circ}

Thus, the measure of ∠E is 81°

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Find the Surface Area of the cone.
Snezhnost [94]

Answer:

\sf \huge{\boxed{\sf area = 653.1 cm^2}}

<u>Explanation</u>:

\sf \boxed{\sf area \ of  \ cone=\pi r^2 +\pi rl }

<u>Given:</u>

  • radius: 8 m
  • slant height: 18 m

<u>using this formula:</u>

\hookrightarrow \sf \pi r^2 + \pi rl

\hookrightarrow \sf (3.14)(8)^2 +(3.14)(8)(18)

\hookrightarrow \sf 653.1 cm^2

7 0
2 years ago
What is the surface area of a cube whose edges are 11 inches long?
Dennis_Churaev [7]
Surface area is the total area of the surface. A cube has 6 surface, and each surface is the same. Each surface is a 11 by 11 square. Therefore there will be 6 11in. x 11in. surfaces. The math would be 11x11x6 =726.
8 0
3 years ago
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How many sides do 1 triangle, 1 decagon, and 5 pentagons have in all?
gregori [183]

Answer:38

Step-by-step explanation:

triangle=3*1=3

decagon=10*1=10

pentagon=5*5=25

3+10+25=38

3 0
3 years ago
Let P be a predicate. Determine whether or not each of the following implications is true and give a brief English explanation f
den301095 [7]

Answer:

See answer below

Step-by-step explanation:

1), Probably, your implication is ∀x∃yP(x,y)⇒∃x∀yP(x,y).

This implication is false. Consider the predicate P(x,y):="x<y" for real numbers x,y. Then, ∀x∃yP(x,y) is true: for all real x, there exists some y greater than x (take y=x+1 for example). However, ∃x∀yP(x,y) is false, as it would imply that there exists some real number x such that x is smaller than all real numbers, which is not true (real numbers do not have a minimum or a lower bound).

A short explanation would be, even if for all elements you can find one that makes a predicate true, you can not find one element that makes the predicate true for all elements.

2) Again, I assume that the predicate is ∃x∀yP(x,y)⇒∀x∃yP(x,y)

This implication is false. Consider the predicate P(x,y):="x is integer and xy=0 " for real numbers x,y. Then ∃x∀yP(x,y) is true, we need to take x=0. However, ∀x∃yP(x,y) is false, if you take x=1/2, 1/2 will never be an integer, no matter the value of y.

A short explanation would be, even if you can find one element that makes a predicate true for all elements, you can not always take an arbitrary element and find some element that makes the predicate true.

6 0
3 years ago
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QveST [7]

Answer:

yes

Step-by-step explanation:

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