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3 years ago

The square root is a number, decreased by 2, is 4.

Mathematics

2 answers:

Anon25 [30]3 years ago

8 0

4 = √(x) - 2. First, add 2 to each side.

6 = √(x). Take each number to the power of 2.

36 = x.

Your number is 36.

olasank [31]3 years ago

4 0

Answer: 36

Step-by-step explanation:

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Police use photographs of various facial features help witnesses identify suspects. One basic identification kit contains 195 ha

Brrunno [24]

Answer: 99 different faces

Step-by-step explanation:

Since a witness can clearly remember the hairline and the eyes and eyebrows of a suspect, and the

basic identification kit contains 195 hairlines, 99 eyes and eyebrows, the number of different faces that can be produced with this information will be 99

5 0

3 years ago

What is the answer to this problem <br>3 over 5=c+1 over 4

balandron [24]

The steps are on the picture! Let me know if you have any questions

5 0

3 years ago

Pls help :( Will mark as brainliest

bagirrra123 [75]

Answer: The only correct answer is 8/18. See below

Step-by-step explanation:

All you need to do is divide the denominator of 9 into the denominator of each fraction, and multiply the numerator by the same factor like this:

4/9 = ?/36; 36/9 = 4; 4x4 =16, so we know that 4/9=16/36 NOT 20/36

4/9 = ?/18; 18/9 =2; 2x4 =8, so we know that 5/9 = 8/18 so YES.

4/9 = ?/45; 45/9=5; 5x4 = 20, so we know that 5/9 = 20/45 NOT 24/45

5/9 = ?/27; 27/9 =3; 3x5 = 15, so we know that 5/9 = 15/27 NOT 12/27

8 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.