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iris [78.8K]
3 years ago
12

Solve 2x^2– 5= 3x with the quadratic formula

Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

see below

Step-by-step explanation:

2x^2-3x-5=0

Well a=2, b=-3, c=-5

x=\frac{-(-3)+-\sqrt{(-3)^2-4(2)(-5)} }{2*2}\\\\ x_1=\frac{3+\sqrt{49} }{4} =\frac{3+7}{4} =\frac{10}{4} =\frac{5}{4} \\\\x_2=\frac{3-\sqrt{49} }{4} =\frac{3-7}{4}=\frac{-4}{4} =-1

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Answer:

(D). 6.

Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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4 years ago
Can you’ll help me pls
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Answer:

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