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ki77a [65]
4 years ago
7

PLEASE HELP ME I BEG YOU PLEASE HELP ME

Mathematics
1 answer:
Shalnov [3]4 years ago
5 0
If measured or given X and L values are 99 mm and 154 mm respectively. Then ..
(a.)
nλ = (1/500)(99/154)
where n = integer

nλ = 0.0012857 mm
mm × 10^6 = nm
nλ = 1286 nm

(b.)
nλ = (1/1000)(99/154)
where n = integer

nλ = 0.0006428 mm
mm × 10^6 = nm
nλ = 643 nm





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The answer is <span>2(–4y + 13) – 3y = –29

Step 1: Express </span><span>x from the second equation
Step 2: Substitute x into the first equation:

The system of equations is:
</span><span>2x – 3y = –29 
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Step 1: 
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Rearrange it to get x:         x = - 4y + 13

Step 2:
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Step-by-step explanation:

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