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Mnenie [13.5K]
3 years ago
7

PLEASE HURRY -4 3/5 divid by 1 1/5

Mathematics
1 answer:
kaheart [24]3 years ago
4 0

The answer is: -3 5/6

Hope this helped :3

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What are the requirements that must be satisfied for a sample to be random? Check all that apply. a. Each individual has an equa
Phantasy [73]

Answer:

<h3>The requirement that must be satisfied for a sample to be random is <u>" Each individual has an equal chance of being selected "</u></h3>

Step-by-step explanation:

<h3>The requirement that must be satisfied for a sample to be random is <u>" Each individual has an equal chance of being selected "</u></h3><h3>Therefore option a) " Each individual has an equal chance of being selected " is correct</h3>
  • Simple random sampling is a method used to cull a smaller sample size from a larger population
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8 0
3 years ago
Commutative<br> property of addition of 93+ (68+7)
givi [52]
93 + (68 + 7)

(93 + 68) + 7

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hope this helps
6 0
3 years ago
0.90[2.25[4]+1.40[3]+6]
Helga [31]

Answer:  17.28

Step-by-step explanation:

Simplify

0.9((2.25)(4)+(1.4)(3)+6)

=(0.9)((2.25)(4)+(1.4)(3)+6)

=(0.9)((2.25)(4))+(0.9)((1.4)(3))+(0.9)(6)

=8.1+3.78+5.4

=17.28

8 0
3 years ago
A good will do one of both of which two things select two answers
goldfiish [28.3K]
WUT?
MARK ME BRAINLEST
3 0
2 years ago
How do you substitute x+y=2 3x+2y=5
Monica [59]
Here's how you solve this.  So, x+y=2, right?  Let's isolate x.  x+y-y=2-y.  x=2-y.  NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y!  3x+2y=5.  3(2-y)+2y=5.  (3*2)+(3*-y)+2y=5.  6+(-3y)+2y=5.  6+(-y)=5.  6+(-y)-6=5-6.  -y=-1.  -y/-1=-1/-1.  y=1.

So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2.  x+1=2.  x+1-1=2-1.  x=1.  1+1=2, so that works; let's check the other equation.  3(1)+2(1)=5.  3+2=5.  5=5.  That's correct!

Answer: x=1, y=1
4 0
3 years ago
Read 2 more answers
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