You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?
1 answer:
Answer:
20
Step-by-step explanation:
Once you give 1 candy to each of the 4 kids, you will have 3 remaining. The number of ways those can be distributed to 4 kids is given by ...
(n+k-1)C(n)
where n is the number of candies, and k is the number of kids. "aCb" is the number of ways a can be taken b at a time:
aCb = a!/(b!(a-b)!)
For n=3 and k=4, this is ...
(3+4-1)C(3) = 6C3 = 6!/(3!·3!) = 20
There are 20 ways to distribute 7 candies to 4 kids so that each kid receives at least one.
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723/100 is the answer to your question!
52/8= what comes closest to 52, well 6x8=48, 7x8=56, we use 48, 52-48=4
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Hello!
Answer:
angle 1 = 100
angle 2 = 80
angle 4 = 105
angle 6 = 100
angle 7 = 105
angle 8 = 75
angle 9 = 100
angle 10 = 80
angle 11 = 75
angle 12 = 105
angle 13 = 80
angle 14 = 100
angle 15 = 105
angle 16 = 75
Use the distance formula to find base and height.
