You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this?
1 answer:
Answer:
20
Step-by-step explanation:
Once you give 1 candy to each of the 4 kids, you will have 3 remaining. The number of ways those can be distributed to 4 kids is given by ...
(n+k-1)C(n)
where n is the number of candies, and k is the number of kids. "aCb" is the number of ways a can be taken b at a time:
aCb = a!/(b!(a-b)!)
For n=3 and k=4, this is ...
(3+4-1)C(3) = 6C3 = 6!/(3!·3!) = 20
There are 20 ways to distribute 7 candies to 4 kids so that each kid receives at least one.
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Answer:
find all numbers, stick together o make an uqaion and solve . simplifi if needed
Step-by-step explanation:
Answer:
The answer is 41
Step-by-step explanation:
(35 + 7) (6 - 5)
(42) × (1) = 41
Thus, The answer is 41
<u>-TheUnknownScientist</u>
Substitute with y = 4 and z = -2
= 4^2*(-2)/4 + 10
= 16*(-2)/4 + 10
= -32/4 + 10
= -8 + 10
= 2
Hope This Helped! Good Luck!
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HELLO! im confused do u want us to answer all of them:D?
Step-by-step explanation:
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Answer:
B x^9 ∛ y
Step-by-step explanation:
(x^27 y) ^ (1/3)
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We can distribute the exponent a^b ^c = a^(b*c)
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x^9 y^(1/3)
