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2 years ago

A. Refer to the measures of two angles that are given.

Mathematics

1 answer:

Mazyrski [523]2 years ago

3 0

Hello!

Answer:

angle 1 = 100

angle 2 = 80

angle 4 = 105

angle 6 = 100

angle 7 = 105

angle 8 = 75

angle 9 = 100

angle 10 = 80

angle 11 = 75

angle 12 = 105

angle 13 = 80

angle 14 = 100

angle 15 = 105

angle 16 = 75

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(1.5 ? 10^2) X (2.0 ? 10^3) Express your answer in scientific notation and standard form.

ludmilkaskok [199]

Answer: 3*10^5 or 300,000 cant remember witch one it is

Step-by-step explanation:

1.5*10^2= 150

2*10^3=2,000

150*2000=300,000

3*10^5

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3 years ago

2x − y = −4→10x − 5y = −20 3x 5y = 59→3x 5y = 59 13x = 39 which equation can replace 3x 5y = 59 in the original system and still

malfutka [58]

13x = 39 can replace 3x + 5y = 59 in the original system and still produce the same solution.

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3 years ago

Lisa buys a dozen apples and two oranges. Jeremy buys six apples. Oranges cost $1 each, and they spent $9 total. How could you d

Vlad [161]

2 oranges cost $2 . $9 - $2 = $7
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3 years ago

Read 2 more answers

You are given the system of equations to solve by the elimination method, which is an INCORRECT step that will NOT produce a sys

Karo-lina-s [1.5K]

C would be the correct answer. You caanot multiply just one part of an equation, you must multiply the whole thing. All of the other steps follow this rule, so C is an incorrect step, and is therefore the correct choice.

Hope this helps!

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3 years ago

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In a jar, there is a green, a blue, and a red marble. You draw (with replacement) a marble from the jar until you get the green

denpristay [2]

Answer:

The value is $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

Step-by-step explanation:

From question we are told that

The number of types of marbles present jar is n = 3

Generally the probability of drawing a green marble is

$P(g) = \frac{1}{3}$

Generally the probability of drawing a marble that is not green is

$P(g') = 1 - \frac{1}{3} = \frac{2}{3}$

From the question we are told that there will be continuous drawing of marbles from the jar (in such a way that after each marble is drawn it is being replaced) until a green marble drawn

Let m be the number of times marbles has been drawn when a green marble was gotten

it then means that for m - 1 times the marbles where drawn a green marble was not obtain.

Generally the probability drawing m times is mathematically is mathematically represented as

$P( X = m ) = (P(g'))^{m-1 } * P(g)$

=> $P( X = m ) = (\frac{2}{3} )^{m-1 } * \frac{1}{3}$

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3 years ago