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Gemiola [76]
3 years ago
12

Help please I'm confused. I'll give a brainliest

Mathematics
2 answers:
krek1111 [17]3 years ago
5 0
The answer for the question is A. always 
murzikaleks [220]3 years ago
4 0
They are always parallel, parallel lines never ever intersect, if that help please mark brainlist
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Find the sum.<br><br><br> (2x-6)+(4x-12)<br><br> Please and thank you
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Answer:

6x - 18

Step-by-step explanation:

Haha i finished first

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Cavalieri's principle states that if two solids of equal height have equal cross-sectional areas at every level parallel to the respective bases, then the two solids have equal volume.

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What angle relationship Describes angles CBE and DEB? I need answered back quick​
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same-side interior angles

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Help me guys <br> thx so much
navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
4 years ago
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If f(x) = 2x² – 2. what is f(-6)?<br> If<br> -78<br> 30<br> 18<br> 0 78<br><br> PLS HELP
blondinia [14]

Answer:

70

Step-by-step explanation:

Substitute x with -6:

2(-6)²-2

2(36)-2

72-2

70

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2 years ago
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