Which is a solution to the equation?

Mathematics

2 answers:

Alona [7]2 years ago

8 0

The answer is -7 letter B

stiks02 [169]2 years ago

3 0

If you would like to know the solution to the equation (x - 2) * (x + 5) = 18, you can calculate this using the following steps:

(x - 2) * (x + 5<span>) = 18
</span>x^2 + 5x - 2x - 10 = 18
x^2 + 3x - 28 = 0
(x + 7) * (x - 4) = 0
1. x = - 7
2. x = 4

The correct result would be x = - 7.

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A box of granola bars has 26 bars. If 7 friends split the bars equally, how many bars will be left?

Vinvika [58]

It will be 5 because 7x3 is 21, minus 26 to 21 is 5, won't be 7x4=28 and that's greater than 26

6 0

2 years ago

A chain of retail computer stores opened 2 stores in its first year of operation. After 8 years of operation, the chain consiste

Helen [10]

Answer:

0.66

Step-by-step explanation:

The exponential growth equation is expressed as;

S(t) = S0e^kt

S(t) is the number of stores after t years

S0 is the initial number of stores

If a chain of retail computer stores opened 2 stores in its first year of operation then at t = 1, S(t) = 2. Substitute into the equation;

2 = S0e^k(1)

2 = S0e^k .... 1

Also if after 8 years of operation, the chain consisted of 206 stores, this means at t = 8, S(t) = 206. Substitute into the equation;

206 = S0e^k(1)

206 = S0e^8k .... 2

Next is to calculate the value of k

Divide equation 2 by 1;

$\frac{206}{2} = \frac{S0e^{8k} }{S0e^k }\\103 = e^{7k}\\apply \ ln \ to \ both \ sides\\ln103 = lne^{7k}\\ln103 = 7k\\k = \frac{ln103}{7}\\k = \frac{4.6347}{7} \\k = 0.6621$

Hence the value of k to the nearest hundredth is 0.66

4 0

2 years ago

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic

Artemon [7]

<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

$\sf{\rightarrow{d = kt}}$