Question

Rewrite, differentiate and simplify: 3/(2x)^3

Answer 1

$\frac{dy}{dx}$ = - $\frac{9}{8x^{4} }$

let y = $\frac{3}{(2x)^{3} }$ = $\frac{3}{8}$ $x^{-3}$

differentiate using the power rule

$\frac{d}{dx}$ ($ax^{n}$ ) = na$x^{n-1}$

$\frac{dy}{dx}$ = - $\frac{9}{8}$$x^{-4}$ = - $\frac{9}{8x^{4} }$