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denis-greek [22]
3 years ago
14

For how many years did the reign of terror last

Mathematics
2 answers:
andriy [413]3 years ago
5 0
September 5, 1793 - July 27, 1794
Alexeev081 [22]3 years ago
5 0

Answer:

It lasted for 1 year. 1793-1794

Step-by-step explanation:

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The opening balance of the March billing cycle for Bernice's credit card was $2374. If she makes a new purchase of $200 on the 2
Norma-Jean [14]

The opening balance of the March billing cycle for Bernice's credit card = $2374.

Amount of new purchase = $200 on the 20th of March.

She did purchase only of $200 in that March month.

We are given that she didn't do any payment.

So, still she has balance $2374 till end of the month.

Therefore, her average daily balance is $2374.00

So, the correct option is  B. $2374.00.

4 0
3 years ago
Read 2 more answers
Which statement is true? A. 2x – 1 = 13 and x = 6 B. 2x – 1 = 13 and x = 7 C. 2x + 1 = 13 and x = 7 D. 2x – 1 = 13 and x = 11
alexandr1967 [171]

Answer:

B. 2x – 1 = 13 and x = 7

Step-by-step explanation:

We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.

Option A.

2x -1 = 13 and x = 6

Using this value in the equation, we get:

2(6) -1 = 13

12 - 1 = 13

11 = 13, which is not true. Hence this option is not valid

Option B.

2x - 1 = 13 and x = 7

Using the value in the equation, we get:

2(7) - 1 =13

14 - 1 =13

13 = 13, which is true. Hence this option is valid.

Option C.

2x + 1 =13 and x = 7

Using the value in the equation, we get:

2(7) + 1 = 13

15 = 13, which is not true. So this option is not valid

Option D.

2x - 1 = 13 and x = 11

Using this value in the equation, we get:

2(11) - 1 = 13

21 = 13, which is not true. Hence this option is not valid.

6 0
3 years ago
Karan needs to choose between two gym plans. he can either pay a $150 joining fee and a $10 monthly fee, or he can pay a $50 joi
Eva8 [605]

Solution:

Let the cumulative costs of the plans will be equal after x months.

Then we can write

150+10x=50+300x\\ \\ 150-50=300x-10x\\ \\ 100=290x\\ \\ x=\frac{100}{290}\\ \\ x=\frac{10}{29}

Hence after 10/29th Month cost will be equal.

and that cost=150+\frac{10}{29} *10=\frac{4450}{29} $

3 0
3 years ago
Help plsss <br> find length..
posledela
I think it’s been awhile but just ur 140/360 then times that by pi then 2 then times r= 12.22
8 0
3 years ago
Robert ran a race that was 2/3 of a mile in length. If he has completed 5/6 of the race, how far has he run in miles?
Darina [25.2K]

Answer:

5/9

Step-by-step explanation:

Let's begin by determining the factors of the problem. We know that Robert ran a race that is 2/3 of a mile long. Therefore, we know that 2/3 is a factor in the equation. We also know that, of the 2/3 mile, he ran 5/6 of it. Now the tricky part is deciding how the two fractions are related.

To make this easier, let's substitute a different number for 5/6. We'll say 2.

If he has completed TWICE the length of the race, how would you determine how far he ran?

You would multiply 2/3 by 2! This same principle can be applied to the problem.

To determine the total distance run in miles, we can write it as 2/3 * 5/6

(NOTE that * is known as "times" or "multiplied by")

With this, you multiply the numerators (2 * 5 = 10) and the denominators (3 * 6 = 18) and then make your fraction... 10/18!

But you're not done yet. Always remember to simplify when possible. Both terms are divisible by 2. Therefore, it can be written as 5/9.

Hope this helped!

7 0
3 years ago
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