Answer:
33/100 red, 29/100 blue
Step-by-step explanation:
2/10=20/100
20+18=38
38/100 orange/clear marbles
100-38=62
62 red/blue marbles
62/2=31
31 blue, 31 red
"There are 2 more red marbles than blue marbles."
31-2=29
31+2=33
33/100 red, 29/100 blue.
Using the dot product:
For any vector x, we have
||x|| = √(x • x)
This means that
||w|| = √(w • w)
… = √((u + z) • (u + z))
… = √((u • u) + (u • z) + (z • u) + (z • z))
… = √(||u||² + 2 (u • z) + ||z||²)
We have
u = ⟨2, 12⟩ ⇒ ||u|| = √(2² + 12²) = 2√37
z = ⟨-7, 5⟩ ⇒ ||z|| = √((-7)² + 5²) = √74
u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46
and so
||w|| = √((2√37)² + 2•46 + (√74)²)
… = √(4•37 + 2•46 + 74)
… = √314 ≈ 17.720
Alternatively, without mentioning the dot product,
w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩
and so
||w|| = √((-5)² + 17²) = √314 ≈ 17.720
<span>fixed annual membership fee of $20
</span><span>$2 per video game rented.
</span><span>Let f(n) represent the total annual cost of renting n video games
so
f(n) = 20 + 2n
if </span><span>increased by $15 the next year
then
f(n) = </span>20 + 2n + 15
f(n) = 2n + 35
answer
<span>f(n) = 2n + 35 (first choice)</span>
You can't change the sum by changing the grouping. Any way you cut it, you will always get 226, as you only have addition operations, and the commutative property [a+(b+c)=(a+b)+c] means that the sum will always be the same.
Answer:
The answer to 34,977* 2,344 is 81986088. Therefore, it is an even number.
Step-by-step explanation:
