All categories

3 years ago

Plz help me get the answer ASAP

Mathematics

1 answer:

AnnyKZ [126]3 years ago

8 0

Answer:

Step-by-step explanation:

$-\dfrac{1}{3}c7\qquad\text{multiply both sides by 3}\\\\c>21$

You might be interested in

The baseball stadium holds 23,564 people. 3/4 of the seats were sold. How many people were in the stadium

Dennis_Churaev [7]

capacity of the stadium=23564

no.of seats occupied=3/4 of 23564

no.of people in the stadium=23564*3/4

=17673

3 0

3 years ago

Read 2 more answers

Find the area of a rectangle that has a length of (x - 5) and a width of (3x + 1).

avanturin [10]

Answer:

A=3x^2 -14x -5

Step-by-step explanation:

(x-5)(3x+1)

3x^2 +x -15x -5

3x^2 -14x -5

5 0

3 years ago

You have a photo that measures 1 in. wide by 3 in. tall. If you want to enlarge the photo so that the height is 18 in., what wil

kiruha [24]

6in... 3 times 6 is 18, so 1 times 6 is 6

4 0

3 years ago

(hurry show ur work) what is 8 6/8 ÷ 2 2/5 = ?

gizmo_the_mogwai [7]

Answer:

175/48 or 3.64

Step-by-step explanation:

■ Refer to the attachment.

Hope it helps ⚜

4 0

2 years ago

Read 2 more answers

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = <u><em>Number of flights that arrive late</em></u>.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago