The equation of a line that goes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so, given the point (-2,8)
x1=-2
y1=8
y-8=m(x-(-2))
y-8=m(x+2)
the equation is y-8=m(x+2) where m is the slope
or you could rewrite it to get y=mx+2m+8
Answer: perimeter = 96mm, Area = 564mm².
Step-by-step explanation:
From the diagram, it is a trapezium, it has a rectangle joined together by a right angled triangle. Now to find the perimeter, we add all the dimensions together. To get the other side of the rectangle, which is also the perpendicular height of the figure, we take the Pythagoras. Let the perpendicular height = x
Therefore,
25² = ײ + 7²
625 = x² + 49
x² = 625 - 49
x² = 576
x. = √576
= 24.
Now the perimeter
= 20 + 25 + 7 + 20 + 24
= 96mm.
Area of the figure will be
= 1/2( a + b )h
Where a = 20, b = 20 + 7 = 27 and h = 24, now substitute for the values
( 20 + 27) x 24
---------------------
2
= 47 x 24/2
= 47 x 12
= 564mm²
Given ---›
y = -3
&
y = x - 0.8
So,
=> x = y + 0.8
=> x = -3 + 0.8
=> x = -2.2
Therefore, the best approximation for the solution to this system of equations is = (–2.2, –3)
A because we all know the intersection of sin is always in (0,0) but in this case it is different
