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Anna [14]
3 years ago
9

Which number should each side of the equation 34x=9 be multiplied by to produce the equivalent equation of x = 12?

Mathematics
2 answers:
zhuklara [117]3 years ago
5 0

For this case, we have the following equation:

\frac {3} {4} x = 9

We must find a number that when multiplied on both sides of the equation, as a result:

x = 12

So, if we multiply 9 * \frac {4} {3} = 12

Now, the left side must also be multiplied by \frac {4} {3}so as not to alter the equation:

\frac {3} {4} x * \frac {4} {3} = x

Finally we havex = 12

Thus, the number is \frac {4} {3}

Answer:

Option C

Tanzania [10]3 years ago
4 0

Answer:

C. 4/3

Step-by-step explanation:

The original equation is [3/4]x = 9

To solve for x, you have to multiply both sides by 4/3

[4/3] ×[3/4]x = 9×[4/3]

x = 36/3 = 12

Answer: C. 4/3

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
The question is in the screenshot
Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

8 0
3 years ago
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