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Solnce55 [7]
3 years ago
5

2 EASY QUESTIONS HELP

Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

a) 5/8

b)6/7

Step-by-step explanation:

You might be interested in
How many lines of symmetry does this figure have?
Sergeeva-Olga [200]

Answer:

2

Step-by-step explanation:

There are two lines of symmetry and here I list them:

1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).

2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.

A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.

So, we only have 2 symmetry lines.

4 0
3 years ago
Find the missing terms in each arithmetic sequence <br> 1,__,__,-17<br> 2,__,__,20
Galina-37 [17]

Answer:

-5,-11

8,14

Step-by-step explanation:

Let 's say r the commun difference

1)

1,1+r,1+2r,1+3r=-17

1+3r=-17

3r=-18

r=-6

Sequence is 1,-5,-11,-17

2)

2,2+r,2+2r,2+3r=20

2+3r=20

3r=18

r=6

Sequence is 2,8,14,20

4 0
2 years ago
arthur wants to buy an item that costs p dollars before tax. using a 6% sales tax rate, write two different expressions that rep
Mkey [24]

For this case we have the following variable:

p: cost of the item that Arthur wants to buy before tax

The expression for the 6% tax is given by:

\frac{6}{100} p

Or equivalently:

0.06p

Therefore, two different expressions for the total cost are:

Expression 1:

p + \frac{6}{100} p

Expression 2:

p + 0.06p

To prove that they are equal, suppose that the item costs $ 100:

Expression 1:

p + \frac{6}{100} p

100+ \frac{6}{100} 100

100 + 6

106

Expression 2:

p + 0.06p

100 + 0.06 (100)

100 + 6

106

Since the cost is the same, then the expressions are the same.

Answer:

Two different expressions that model the problem are:

p + \frac{6}{100} p

p + 0.06p

8 0
3 years ago
Will 1/4 x 7/8 be larger or smaller than 1/4? Explain your answer.
sweet-ann [11.9K]
It will be smaller than 1/4.

The reason being that 7/8 is a fraction which is less than 1, and that it can only be greater than 1/4 when the multiplying number, is a number which is greater than 1.

Note: When  a positive number is multiplied by a number which is less than 1, it makes the positive number to be smaller and

When a positive number is multiplied by a number which is greater than 1, it makes the positive number to be bigger.

5 0
3 years ago
Read 2 more answers
Which statements about the function are true? Select two
iogann1982 [59]

Answer:

The vertex of the function is at (1,-25)

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown  below. </em>

<em>Which statements about the function are true? Select two </em>

<em>options. </em>

<em>The vertex of the function is at (1,-25). </em>

<em>The vertex of the function is at (1,-24). </em>

<em>The graph is increasing only on the interval -4< x < 6. </em>

<em>The graph is positive only on one interval, where x <-4. </em>

<em>The graph is negative on the entire interval  </em>

My answer:

Given the factored form of the function:

f(x) = (x + 4)(x-6)

<=> f(x) = x^{2} - 2x -24

We will convert to vertex form

<=> f(x) = (x^{2} - 2x +1) - 25

<=> f(x) = (x-1)^{2} -25

=> the vertex of the function is: (1,-25)

We choose: a. The vertex of the function is at (1,-25)

Let analyse other possible answers:

<u>c. The graph is increasing only on the interval -4< x < 6.</u>

Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.

So the graph is increasing in the domain (1, +∞)

=> C is wrong

<u>d. The graph is positive only on one interval, where x <-4</u>

Wrong, The graph is positive only on one interval, where x > 6

<u>e. The graph is negative on the entire interval</u>

Wrong, The graph is negative only on one interval, where -4< x < 6.

7 0
3 years ago
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