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Ostrovityanka [42]
3 years ago
12

Math question screen shot down below

Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

48

Step-by-step explanation:

1.First u have to order the numbers from least to greatest.

-52,58,66,71,72,79,82,84,85,94,98,100

2.Find the lowest number and the highest number.

-52 nd 100

3.Subtract the 2 numbers

100-52=48

Sav [38]3 years ago
7 0

Answer:

48

Step-by-step explanation:

100-52=48

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Victoria bought a jacket in the sale which had 20% off. If it cost ?36 on sale what did it cost before the sale?
Basile [38]

Answer:

The jacket costs $45

Step-by-step explanation:

In order to find this, notice that the price of the sale represents 80% of the total cost. This is because we took 20% away with the sale. Now we can find the overall amount by dividing the sale cost by the amount it represents.

$36 / 80% = $45

7 0
3 years ago
Yung bought $4.60 worth of bubble gum. Each piece of gum cost $0.10. How many pieces of bubble gum did Yung buy?
Readme [11.4K]

<u><em>Answer:</em></u>

Yung bought 46 pieces of bubble gum for $4.6

<u><em>Explanation:</em></u>

We are given that each piece of gum cost $0.1 and that he spent $4.6 on gums

<u>To get the number of gums he bought, we will simply use cross multiplication as follows:</u>

1 piece .........................> 0.1

x pieces ......................> 4.6

<u>Therefore:</u>

x = \frac{4.6*1}{0.1}= 46 pieces of gum

Hope this helps :)

4 0
3 years ago
Read 2 more answers
I need help doing everything.
ohaa [14]

Using set notations, we have that:

1. The range of the function is:

  • Inequality: x ≥ -15.
  • Set-builder: {x | x ≥ -15}
  • Interval: [-15, ∞).

2. The function is increasing on:

  • Inequality: x > 3.
  • Set-builder: {x | x > 3}
  • Interval: (3, ∞).

3. The function is decreasing on:

  • Inequality: x < 3
  • Set-builder: {x | x < 3}
  • Interval: (-∞, 3).

4. The function is negative on:

  • Inequality: 0.918 < x < 5.082.
  • Set-builder: {x | 0.918 < x < 5.082}.
  • Interval: (0.918, 5.082).

<h3>What is the standard interval notation?</h3>

The standard interval notation of an interval of lower bound a and upper bound b is given by:

[a,b].

The inequality notation is:

a ≤ x ≤ b

The set builder notation is:

{x | a ≤ x ≤ b}.

<h3>What is the range of the function?</h3>

The range of a function is the set that contains all possible output values for the function. In a graph, it is given by the values of y of the function.

Hence, for this problem, the range is given by these following notations:

  • Inequality: x ≥ -15.
  • Set-builder: {x | x ≥ -15}
  • Interval: [-15, ∞).

<h3>When is a quadratic function increasing and when it is decreasing?</h3>

Considering a concave up quadratic function, as given in this problem, we have that:

  • It decays for the values of x before the vertex.
  • It increases for the values of x after the vertex.

In this problem, the vertex is at x = 3, hence the intervals are given as follows:

2. The function is increasing on:

  • Inequality: x > 3.
  • Set-builder: {x | x > 3}
  • Interval: (3, ∞).

3. The function is decreasing on:

  • Inequality: x < 3
  • Set-builder: {x | x < 3}
  • Interval: (-∞, 3).

<h3>When a function is negative?</h3>

A function is negative when it's graph is below the x-axis. Hence, for this problem, we have that:

4. The function is negative on:

  • Inequality: 0.918 < x < 5.082.
  • Set-builder: {x | 0.918 < x < 5.082}.
  • Interval: (0.918, 5.082).

More can be learned about set notations at brainly.com/question/24462379

#SPJ1

6 0
1 year ago
PLZZZ HELP!!
sesenic [268]
First we find list the data in order
Then we find the median
We split the data in half and find the median of the first half which is C
3 0
3 years ago
Read 2 more answers
1. In ABC, C is a right angle and BC = 11. If B = 30°, find AC. (1 point)
faltersainse [42]

Answer:

AC=\frac{11\sqrt{3}}{3}

Step-by-step explanation:

Given that triangle ABC is a right angle triangle. Where angle C is a right angle. Also we have been given that BC = 11, B = 30°. Now we need to find the value of AC.

Apply formula:

\tan\left(\theta\right)=\frac{opposite}{adjacent}

\tan\left(B\right)=\frac{AC}{BC}

\tan\left(30^o\right)=\frac{AC}{11}

\frac{1}{\sqrt{3}}=\frac{AC}{11}

\frac{11}{\sqrt{3}}=AC

AC=\frac{11}{\sqrt{3}}

or

AC=\frac{11}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}

or

AC=\frac{11\sqrt{3}}{3}

Hence final answer is AC=\frac{11\sqrt{3}}{3}.

7 0
3 years ago
Read 2 more answers
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